Evaluate (27/64)^(1/3). Factorise completely pq-3p-q2+3q. Simplify 8x+4-3(2x-3).

A power of $\frac{1}{3}$ means taking the cube root.

$$\left(\frac{27}{64}\right)^{\frac{1}{3}} = \frac{27^{\frac{1}{3}}}{64^{\frac{1}{3}}}$$

$$\frac{\sqrt[3]{27}}{\sqrt[3]{64}} = \frac{3}{4}$$

The final answer is $\boxed{\frac{3}{4}}$.

2. Factorise completely $pq - 3p - q^2 + 3q$.

$$(q - 3)(p - q)$$

The final answer is $\boxed{(q - 3)(p - q)}$.

3. Simplify $8x + 4 - 3(2x - 3)$.

$$8x + 4 - 3(2x) - 3(-3)$$ $$8x + 4 - 6x + 9$$

$$2x + 13$$

The final answer is $\boxed{2x + 13}$.