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27 = sqrt(34) sqrt(20) cos(theta)

Mathematics

ScanSolve AI Answer

Step-by-step solution

6 steps

Here's how to solve the equation for θ\theta:

  1. Write down the given equation.

    27=34×20×cos⁡θ27 = \sqrt{34} \times \sqrt{20} \times \cos\theta
  2. Simplify the product of the square roots.

    We can combine the square roots: a×b=a×b\sqrt{a} \times \sqrt{b} = \sqrt{a \times b}.

    34×20=34×20=680\sqrt{34} \times \sqrt{20} = \sqrt{34 \times 20} = \sqrt{680}
  3. Substitute the simplified term back into the equation.

    27=680×cos⁡θ27 = \sqrt{680} \times \cos\theta
  4. Isolate cos⁡θ\cos\theta.

    Divide both sides by 680\sqrt{680}:

    cos⁡θ=27680\cos\theta = \frac{27}{\sqrt{680}}
  5. Evaluate the numerical value of cos⁡θ\cos\theta.

    680≈26.0768\sqrt{680} \approx 26.0768 cos⁡θ≈2726.0768≈1.0354\cos\theta \approx \frac{27}{26.0768} \approx 1.0354
  6. Determine the solution for θ\theta.

    The range of the cosine function is [−1,1][-1, 1]. Since the calculated value for cos⁡θ\cos\theta (approximately 1.0354) is greater than 1, there is no real angle θ\theta that satisfies this equation.

    Therefore, there is no real solution for θ\theta.

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