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(4) On a pair of axes, construct a rhombus. Find the equation of each side. What do you notice? Investigate for different quadrilaterals.

Mathematics

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  1. Define the vertices of a rhombus.

    To construct a rhombus on a pair of axes, we define its vertices. Let's choose the vertices A=(0,3)A=(0,3), B=(4,0)B=(4,0), C=(0,−3)C=(0,-3), and D=(−4,0)D=(-4,0).

  2. Find the equation of side AB.

    Using points A(0,3)A(0,3) and B(4,0)B(4,0), the slope is mAB=0−34−0=−34m_{AB} = \frac{0-3}{4-0} = -\frac{3}{4}.
    The equation of the line is y−3=−34(x−0)y - 3 = -\frac{3}{4}(x - 0).

    4(y−3)=−3x4(y - 3) = -3x 4y−12=−3x4y - 12 = -3x 3x+4y=12\boxed{3x + 4y = 12}
  3. Find the equation of side BC.

    Using points B(4,0)B(4,0) and C(0,−3)C(0,-3), the slope is mBC=−3−00−4=−3−4=34m_{BC} = \frac{-3-0}{0-4} = \frac{-3}{-4} = \frac{3}{4}.
    The equation of the line is y−0=34(x−4)y - 0 = \frac{3}{4}(x - 4).

    4y=3(x−4)4y = 3(x - 4) 4y=3x−124y = 3x - 12 3x−4y=12\boxed{3x - 4y = 12}
  4. Find the equation of side CD.

    Using points C(0,−3)C(0,-3) and D(−4,0)D(-4,0), the slope is mCD=0−(−3)−4−0=3−4=−34m_{CD} = \frac{0-(-3)}{-4-0} = \frac{3}{-4} = -\frac{3}{4}.
    The equation of the line is y−(−3)=−34(x−0)y - (-3) = -\frac{3}{4}(x - 0).

    4(y+3)=−3x4(y + 3) = -3x 4y+12=−3x4y + 12 = -3x 3x+4y=−12\boxed{3x + 4y = -12}
  5. Find the equation of side DA.

    Using points D(−4,0)D(-4,0) and A(0,3)A(0,3), the slope is mDA=3−00−(−4)=34m_{DA} = \frac{3-0}{0-(-4)} = \frac{3}{4}.
    The equation of the line is y−0=34(x−(−4))y - 0 = \frac{3}{4}(x - (-4)).

    4y=3(x+4)4y = 3(x + 4) 4y=3x+124y = 3x + 12 3x−4y=−12\boxed{3x - 4y = -12}
  6. What do you notice?

    We notice that:

    • Opposite sides have the same slope (mAB=mCD=−34m_{AB} = m_{CD} = -\frac{3}{4} and mBC=mDA=34m_{BC} = m_{DA} = \frac{3}{4}), indicating that opposite sides are parallel.
    • The equations of opposite sides (e.g., 3x+4y=123x+4y=12 and 3x+4y=−123x+4y=-12) share the same xx and yy coefficients, differing only in the constant term. This is characteristic of parallel lines.
  7. Investigate for different quadrilaterals.

    • A parallelogram will also have opposite sides with the same slope, meaning their equations will differ only by a constant.
    • A rectangle is a parallelogram with adjacent sides perpendicular. This means the product of the slopes of adjacent sides will be −1-1.
    • A square is a rectangle with all sides equal. It will exhibit both parallel opposite sides and perpendicular adjacent sides.
    • A trapezium (or trapezoid) has only one pair of opposite sides that are parallel, so only two of its side equations will have the same slope.
    • A kite has two pairs of equal-length adjacent sides. There is no general rule for the slopes of its sides, but its diagonals are perpendicular.
    • A general quadrilateral has no specific relationships between the slopes or equations of its sides.
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