A bucket is 12cm in diameter at the top, 8cm in diameter at the bottom and 4cm deep. Calculate its volume in cm3 [JANB]

The bucket is a frustum of a cone.
Top diameter ($D_1$) = 12 cm, so top radius ($R_1$) = $\frac{12}{2} = 6$ cm.
Bottom diameter ($D_2$) = 8 cm, so bottom radius ($R_2$) = $\frac{8}{2} = 4$ cm.
Depth (height, $h$) = 4 cm.

The volume $V$ of a frustum of a cone is given by the formula:

Substitute $h = 4$ cm, $R_1 = 6$ cm, and $R_2 = 4$ cm into the formula:

Using $\pi \approx 3.14159$:

The volume of the bucket is $\frac{304}{3} \pi \text{ cm}^3 \approx 318.90 \text{ cm}^3$.