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A) Calculate the total water used in 3 days if Day 1 used sqrt(5)L, Day 2 used 2sqrt(5)L, and Day 3 used 3sqrt(5)L. b) Calculate the total cost if water costs Ksh 15 per litre.

Mathematics

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Here are the solutions to the questions:

  1. a)
  1. Identify the water used each day.

    Day 1: 5\sqrt{5} litres
    Day 2: 252\sqrt{5} litres
    Day 3: 353\sqrt{5} litres

  2. Add the amounts to find the total water used.

    Total water =5+25+35= \sqrt{5} + 2\sqrt{5} + 3\sqrt{5}
    Total water =(1+2+3)5= (1 + 2 + 3)\sqrt{5}
    Total water =65= 6\sqrt{5} litres
    The total water used is 65 litres\boxed{6\sqrt{5} \text{ litres}}.

    b)

  3. Identify the cost per litre and the total water used.

    Cost per litre = Ksh 15
    Total water used = 656\sqrt{5} litres

  4. Calculate the total cost.

    Total cost =Total water used×Cost per litre= \text{Total water used} \times \text{Cost per litre}
    Total cost =65×15= 6\sqrt{5} \times 15
    Total cost =905= 90\sqrt{5} Ksh
    The total cost is 905 Ksh\boxed{90\sqrt{5} \text{ Ksh}}.

    1. a)
  5. Identify the battery life of one device.

    Battery life of one device =11= \sqrt{11} hours

  6. Calculate the total time for 8 phones.

    Total time for 8 phones =8×11= 8 \times \sqrt{11}
    Total time for 8 phones =811= 8\sqrt{11} hours
    The total time for 8 phones is 811 hours\boxed{8\sqrt{11} \text{ hours}}.

    b)

  7. Write the expression to be rationalized.

    Expression =411= \frac{4}{\sqrt{11}}

  8. Multiply the numerator and denominator by 11\sqrt{11} to rationalize.

    411=411×1111\frac{4}{\sqrt{11}} = \frac{4}{\sqrt{11}} \times \frac{\sqrt{11}}{\sqrt{11}} =41111= \frac{4\sqrt{11}}{11}

    The rationalized expression is ∗41111∗\boxed*{\frac{4\sqrt{11}}{11}*}.

    1. a)
  9. Write the expression.

    Expression =2x2−13x+20= 2x^2 - 13x + 20

  10. Find two numbers that multiply to (2×20=40)(2 \times 20 = 40) and add to −13-13.

    The numbers are −5-5 and −8-8.

  11. Rewrite the middle term using these numbers.

    2x2−5x−8x+202x^2 - 5x - 8x + 20
  12. Group terms and factor out common factors.

    (2x2−5x)−(8x−20)(2x^2 - 5x) - (8x - 20) x(2x−5)−4(2x−5)x(2x - 5) - 4(2x - 5)
  13. Factor out the common binomial.

    (2x−5)(x−4)(2x - 5)(x - 4)

    The factorized expression is (2x−5)(x−4)\boxed{(2x - 5)(x - 4)} .

    b)

  14. Write the equation.

    2x2−13x+20=02x^2 - 13x + 20 = 0
  15. Use the factorized form from part (a).

    (2x−5)(x−4)=0(2x - 5)(x - 4) = 0
  16. Set each factor equal to zero and solve for xx.

    2x−5=0orx−4=02x - 5 = 0 \quad \text{or} \quad x - 4 = 0 2x=5orx=42x = 5 \quad \text{or} \quad x = 4 x=52orx=4x = \frac{5}{2} \quad \text{or} \quad x = 4

    The solutions are ∗x=52 and x=4∗\boxed*{x = \frac{5}{2} \text{ and } x = 4*}.

    1. a)
  17. Write the expression.

    F=a3b5a2b3F = \frac{a^3b^5}{a^2b^3}
  18. Apply the index law xmxn=xm−n\frac{x^m}{x^n} = x^{m-n}.

    F=a3−2b5−3F = a^{3-2}b^{5-3} F=a1b2F = a^1b^2 F=ab2F = ab^2

    The simplified expression is ab2\boxed{ab^2}.

    b)

  19. Substitute the given values a=2a = 2 and b=3b = 3 into the simplified expression.

    F=ab2F = ab^2 F=(2)(32)F = (2)(3^2)
  20. Calculate the numerical value.

    F=2×9F = 2 \times 9 F=18F = 18

    The numerical value is 18\boxed{18}.

    1. a)
  21. Write the expression for the area.

    A=x2−4x−21A = x^2 - 4x - 21
  22. Factorize the quadratic expression.

    Find two numbers that multiply to −21-21 and add to −4-4.
    The numbers are −7-7 and 3.

  23. Rewrite the expression in factored form.

    A=(x−7)(x+3)A = (x - 7)(x + 3)

    The dimensions of the garden are (x−7) and (x+3) units\boxed{(x - 7) \text{ and } (x + 3) \text{ units}}. (Assuming units are in metres, for example).

    b)

  24. Determine the perimeter of the garden.

    The dimensions are (x−7)(x - 7) and (x+3)(x + 3).
    Perimeter P=2(length+width)P = 2(\text{length} + \text{width})

    P=2((x+3)+(x−7))P = 2((x + 3) + (x - 7)) P=2(x+3+x−7)P = 2(x + 3 + x - 7) P=2(2x−4)P = 2(2x - 4) P=4x−8 metresP = 4x - 8 \text{ metres}
  25. Calculate the total cost of fencing.

    Cost per metre = KSh 150
    Total cost =Perimeter×Cost per metre= \text{Perimeter} \times \text{Cost per metre}

    Total cost=(4x−8)×150\text{Total cost} = (4x - 8) \times 150 Total cost=150(4x−8)\text{Total cost} = 150(4x - 8) Total cost=600x−1200 Ksh\text{Total cost} = 600x - 1200 \text{ Ksh}

    The cost of fencing the garden is (600x−1200) Ksh\boxed{(600x - 1200) \text{ Ksh}}.

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