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A carpenter needs to cut a wooden plank into 3 equal pieces. The total length of the plank is 4.5 metres. Determine if the length of each piece will be a rational or irrational number.

Mathematics

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Answers

3 parts
1

Namba ya busara\text{Namba ya busara}

2
1188
3
9.3840

Step-by-step solution

10 steps

Part 1· 3 steps

  1. Tafuta urefu wa kila kipande.

    Urefu wa jumla wa ubao ni mita 4.5, na umekatwa katika vipande 3 sawa.

    Urefu wa kipande kimoja=Urefu wa jumlaIdadi ya vipande=4.53\text{Urefu wa kipande kimoja} = \frac{\text{Urefu wa jumla}}{\text{Idadi ya vipande}} = \frac{4.5}{3} Urefu wa kipande kimoja=1.5 mita\text{Urefu wa kipande kimoja} = 1.5 \text{ mita}
  2. Bainisha namba ya busara (rational) na namba isiyo ya busara (irrational).

    Namba ya busara ni namba yoyote inayoweza kuandikwa kama sehemu ab\frac{a}{b}, ambapo aa na bb ni namba kamili na b≠0b \neq 0. Namba isiyo ya busara haiwezi kuandikwa kwa njia hii na ina uwakilishi wa desimali usioisha na usiojirudia.

  3. Amua kama 1.5 ni namba ya busara au isiyo ya busara.

    Namba 1.5 inaweza kuandikwa kama sehemu 1510\frac{15}{10} au 32\frac{3}{2}. Kwa kuwa inaweza kuandikwa kama sehemu ya namba kamili, ni namba ya busara.

    Urefu wa kila kipande utakuwa namba ya busara.

    Namba ya busara\boxed{\text{Namba ya busara}}

Part 21188

  1. Tafuta namba kubwa zaidi ya mchanganyiko (composite number) kati ya 70 na 100.

    Namba ya mchanganyiko ni namba chanya kamili ambayo ina vigawanyiko zaidi ya viwili (1 na yenyewe).
    Namba kuu (prime numbers) kati ya 70 na 100 ni 71, 73, 79, 83, 89, 97.
    Namba kubwa zaidi kati ya 70 na 100 ni 99. Namba 99 ni namba ya mchanganyiko kwa sababu 99=9×1199 = 9 \times 11.

  2. Tafuta namba ndogo zaidi shufwa (even number) kati ya 11 na 20.

    Namba shufwa ni namba inayoweza kugawanywa na 2 bila baki.
    Namba shufwa kati ya 11 na 20 ni 12, 14, 16, 18.
    Namba ndogo zaidi shufwa kati ya hizi ni 12.

  3. Tafuta zao (product) la namba hizi mbili.

    Zao ni matokeo ya kuzidisha namba hizi mbili.

    Zao=99×12\text{Zao} = 99 \times 12 Zao=1188\text{Zao} = 1188 1188\boxed{1188}

Part 39.3840

  1. Andika upya usemi kwa kutumia reciprocals.

    Tunatumia ukweli kwamba ab=a×1b\frac{a}{b} = a \times \frac{1}{b}.

    40.4237−589.79=4×10.4237−5×189.79\frac{4}{0.4237} - \frac{5}{89.79} = 4 \times \frac{1}{0.4237} - 5 \times \frac{1}{89.79}
  2. Tafuta reciprocal ya 0.4237.

    Kutoka kwenye kikokotoo (kwa kukosa jedwali la reciprocals),

    10.4237≈2.359924475\frac{1}{0.4237} \approx 2.359924475
  3. Tafuta reciprocal ya 89.79.

    Kutoka kwenye kikokotoo,

    189.79≈0.0111369083\frac{1}{89.79} \approx 0.0111369083
  4. Badilisha thamani na ufanye hesabu.

    4×2.359924475−5×0.01113690834 \times 2.359924475 - 5 \times 0.0111369083 9.4396979−0.05568454159.4396979 - 0.0556845415 9.38401335859.3840133585

    Kukadiria kwa sehemu nne za desimali:

    9.38409.3840 9.3840\boxed{9.3840}
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