A circle of center O which has a radius of 9cm and angle 85 degrees. Find the length of the chord, the minor arc, the area of the sector formed, and the area of the minor segment.

The length of a chord $L$ is given by $L = 2r \sin\left(\frac{\theta}{2}\right)$.

$$L = 2 \times 9 \times \sin\left(\frac{85^\circ}{2}\right)$$ $$L = 18 \times \sin(42.5^\circ)$$

$$L = 18 \times 0.67559$$ $$L \approx 12.1606$$ $$L \approx 12.2 \text{ cm}$$

The length of the chord is $\boxed{12.2 \text{ cm}}$.

The length of an arc $S$ is given by $S = \frac{\theta}{360^\circ} \times 2\pi r$.

$$S = \frac{85^\circ}{360^\circ} \times 2\pi (9)$$ $$S = \frac{85}{360} \times 18\pi$$

$$S = \frac{85}{20} \pi$$ $$S = 4.25\pi$$ $$S \approx 4.25 \times 3.14159$$ $$S \approx 13.3517$$ $$S \approx 13.4 \text{ cm}$$

The length of the minor arc is $\boxed{13.4 \text{ cm}}$.

The area of a sector $A_{sector}$ is given by $A_{sector} = \frac{\theta}{360^\circ} \times \pi r^2$.

$$A_{sector} = \frac{85^\circ}{360^\circ} \times \pi (9)^2$$ $$A_{sector} = \frac{85}{360} \times 81\pi$$

$$A_{sector} = \frac{17}{72} \times 81\pi$$ $$A_{sector} = \frac{17 \times 9}{8} \pi$$ $$A_{sector} = \frac{153}{8} \pi$$ $$A_{sector} = 19.125\pi$$ $$A_{sector} \approx 19.125 \times 3.14159$$ $$A_{sector} \approx 60.089$$ $$A_{sector} \approx 60.1 \text{ cm}^2$$

The area of the sector formed is $\boxed{60.1 \text{ cm}^2}$.

The area of the triangle $A_{triangle}$ is given by $A_{triangle} = \frac{1}{2} r^2 \sin \theta$.

$$A_{triangle} = \frac{1}{2} (9)^2 \sin(85^\circ)$$ $$A_{triangle} = \frac{1}{2} \times 81 \times \sin(85^\circ)$$ $$A_{triangle} \approx 40.5 \times 0.99619$$ $$A_{triangle} \approx 40.3457 \text{ cm}^2$$

The area of the minor segment $A_{segment}$ is $A_{segment} = A_{sector} - A_{triangle}$.

$$A_{segment} \approx 60.089 - 40.3457$$ $$A_{segment} \approx 19.7433$$ $$A_{segment} \approx 19.7 \text{ cm}^2$$

The area of the minor segment is $\boxed{19.7 \text{ cm}^2}$.

The area of the circle $A_{circle}$ is given by $A_{circle} = \pi r^2$.

$$A_{circle} = \pi (9)^2$$ $$A_{circle} = 81\pi$$ $$A_{circle} \approx 81 \times 3.14159$$ $$A_{circle} \approx 254.469 \text{ cm}^2$$

The area of the major segment $A_{major\_segment}$ is $A_{major\_segment} = A_{circle} - A_{minor\_segment}$.

$$A_{major\_segment} \approx 254.469 - 19.7433$$ $$A_{major\_segment} \approx 234.7257$$ $$A_{major\_segment} \approx 234.7 \text{ cm}^2$$

The area of the major segment is $\boxed{234.7 \text{ cm}^2}$.