A dice is thrown one .find the probably of getting a number divided by 3

Question

ScanSolve AI Tutor · Accepted Answer

When a fair die is thrown once, the possible outcomes are the numbers 1, 2, 3, 4, 5, and 6.

Determine the total number of possible outcomes.
The total number of outcomes when throwing a single die is 6.
Determine the number of favorable outcomes.
We are looking for numbers divisible by 3. From the possible outcomes $\{1, 2, 3, 4, 5, 6\}$ , the numbers divisible by 3 are 3 and 6.
So, there are 2 favorable outcomes.
Calculate the probability.
The probability of an event is given by the formula:
$P(\text{event}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}$ $P(\text{number divisible by 3}) = \frac{2}{6}$ $P(\text{number divisible by 3}) = \frac{1}{3}$
The probability of getting a number divisible by 3 is:
$\frac{1}{3}$

Answer