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A fair die is rolled once. What is the probability of obtaining a 3 or 4?

Mathematics

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Answer

B. 13\text{B. } \frac{1}{3}

Step-by-step solution

4 steps

B. 13\frac{1}{3}

  1. Identify the total number of possible outcomes when rolling a fair die once.

    A standard fair die has 6 faces, numbered 1, 2, 3, 4, 5, 6.
    So, the total number of possible outcomes is 6.

  2. Identify the number of favorable outcomes.

    The question asks for the probability of obtaining a 3 or a 4. The favorable outcomes are 3 and 4.
    There are 2 favorable outcomes.

  3. Calculate the probability.

    The probability of an event is given by the formula:

    P(event)=Number of favorable outcomesTotal number of possible outcomesP(\text{event}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} P(3 or 4)=26P(\text{3 or 4}) = \frac{2}{6}
  4. Simplify the probability.

    26=13\frac{2}{6} = \frac{1}{3}

    The final answer is B. 13\text{B. } \frac{1}{3}.

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