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A hotel charges Le 20.00 per night for one room. At what cost will Mr. Bajah pay for staying in the hotel from February 1 to April 15 inclusive in a leap year.

Mathematics

ScanSolve AI Answer

Answer

Le 39000.00\text{Le } 39000.00

Step-by-step solution

3 steps
  1. Calculate the number of nights Mr.

    Bayah stayed in the hotel.
    Since it is a leap year, February has 29 days.

    • Number of nights in February (from Feb 1 to Feb 29 inclusive): 29−1+1=2929 - 1 + 1 = 29 nights
    • Number of nights in March (from Mar 1 to Mar 31 inclusive): 31−1+1=3131 - 1 + 1 = 31 nights
    • Number of nights in April (from Apr 1 to Apr 15 inclusive): 15−1+1=1515 - 1 + 1 = 15 nights
  2. Calculate the total number of nights.

    Total nights=29+31+15=75 nights\text{Total nights} = 29 + 31 + 15 = 75 \text{ nights}
  3. Calculate the total cost.

    The cost per night is Le 520.00.

    Total cost=Total nights×Cost per night\text{Total cost} = \text{Total nights} \times \text{Cost per night} Total cost=75×Le 520.00\text{Total cost} = 75 \times \text{Le } 520.00 Total cost=Le 39000.00\text{Total cost} = \text{Le } 39000.00

    The total cost Mr. Bayah will pay is:

    Le 39000.00\text{Le } 39000.00
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