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A. How many of each vehicle type should be worked on? b. Determine the maximum number of bags of cement that he should buy to meet his budget.

Mathematics

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Answers

2 parts
a

10 mabasi\text{10 mabasi}

0 coasters\text{0 coasters}

b

75 mifuko\text{75 mifuko}

Step-by-step solution

8 steps

Part a· 5 steps

Idadi ya kila aina ya gari zinazopaswa kutumika

  1. Tambua vigezo na tengeneza milinganyo.

    Acha BB iwe idadi ya mabasi na CC iwe idadi ya coasters.
    Mabasi hubeba abiria 70, coasters hubeba abiria 35. Jumla ya abiria ni 700.

    70B+35C=70070B + 35C = 700

    Kuna madereva 10, na kila gari linahitaji dereva mmoja.

    B+C≤10B + C \le 10

    Idadi ya magari haiwezi kuwa hasi:

    B≥0,C≥0B \ge 0, \quad C \ge 0
  2. Rahisisha mlinganyo wa abiria na utatue kwa CC.

    Gawanya mlinganyo wa abiria kwa 35:

    70B35+35C35=70035\frac{70B}{35} + \frac{35C}{35} = \frac{700}{35} 2B+C=202B + C = 20

    Tenga CC:

    C=20−2BC = 20 - 2B
  3. Badilisha CC kwenye mlinganyo wa madereva na utatue kwa BB.

    B+(20−2B)≤10B + (20 - 2B) \le 10 20−B≤1020 - B \le 10 −B≤10−20-B \le 10 - 20 −B≤−10-B \le -10

    Kuzidisha kwa −1-1 kunabadilisha mwelekeo wa usawa:

    B≥10B \ge 10
  4. Tumia masharti ya C≥0C \ge 0.

    Kwa kuwa C=20−2BC = 20 - 2B na C≥0C \ge 0:

    20−2B≥020 - 2B \ge 0 20≥2B20 \ge 2B B≤10B \le 10
  5. Pata thamani za BB na CC.

    Kutoka Step 3, B≥10B \ge 10. Kutoka Step 4, B≤10B \le 10.
    Hivyo, thamani pekee inayowezekana kwa BB ni 10.
    Badilisha B=10B=10 kwenye C=20−2BC = 20 - 2B:

    C=20−2(10)C = 20 - 2(10) C=20−20C = 20 - 20 C=0C = 0

    Idadi ya mabasi: 10 mabasi\boxed{\text{10 mabasi}}
    Idadi ya coasters: 0 coasters\boxed{\text{0 coasters}}

Part b

75 mifuko\text{75 mifuko}

Idadi kubwa zaidi ya mifuko ya saruji anayopaswa kununua

  1. Tambua gharama kwa kila mfuko na bajeti.

    Gharama ya mfuko mmoja wa saruji = 20,000.
    Bajeti ya mkandarasi = 1,500,000.

  2. Tengeneza mlinganyo wa kutafuta idadi kubwa zaidi ya mifuko.

    Acha NN iwe idadi ya mifuko ya saruji.
    Gharama ya jumla ya mifuko haiwezi kuzidi bajeti:

    N×20,000≤1,500,000N \times 20,000 \le 1,500,000
  3. Tatua kwa NN.

    N≤1,500,00020,000N \le \frac{1,500,000}{20,000} N≤1502N \le \frac{150}{2} N≤75N \le 75

    Idadi kubwa zaidi ya mifuko ya saruji: 75 mifuko\boxed{\text{75 mifuko}}

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