A Man need to carry 10 bags of Cement for along a distance of 10m. Each bag of Cement is 10kg. Knowing that work done is Force x Distance. Calculate the Energy needed in Kcals to transport the Bags.

Physics

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Answer

2.34 Kcals\text{2.34 Kcals}

Step-by-step solution

5 steps
  1. Calculate the total mass of the cement bags.

    The total mass (MM) is the number of bags multiplied by the mass of each bag.

    M=10 bags×10 kg/bag=100 kgM = 10 \text{ bags} \times 10 \text{ kg/bag} = 100 \text{ kg}
  2. Calculate the force required to carry the bags.

    The force (FF) needed to carry the bags is equal to their weight. We use the acceleration due to gravity (g≈9.81 m/s2g \approx 9.81 \text{ m/s}^2).

    F=M×gF = M \times g F=100 kg×9.81 m/s2=981 NF = 100 \text{ kg} \times 9.81 \text{ m/s}^2 = 981 \text{ N}
  3. Calculate the work done.

    Work done (WW) is given by the formula Force ×\times Distance.

    W=F×DistanceW = F \times \text{Distance} W=981 N×10 m=9810 JW = 981 \text{ N} \times 10 \text{ m} = 9810 \text{ J}
  4. Convert the work done from Joules to calories.

    We know that 1 calorie=4.184 Joules1 \text{ calorie} = 4.184 \text{ Joules}.

    Wcalories=9810 J4.184 J/calorieW_{\text{calories}} = \frac{9810 \text{ J}}{4.184 \text{ J/calorie}} Wcalories≈2344.646 caloriesW_{\text{calories}} \approx 2344.646 \text{ calories}
  5. Convert calories to kilocalories (Kcals).

    We know that 1 Kcal=1000 calories1 \text{ Kcal} = 1000 \text{ calories}.

    WKcals=2344.646 calories1000 calories/KcalW_{\text{Kcals}} = \frac{2344.646 \text{ calories}}{1000 \text{ calories/Kcal}} WKcals≈2.3446 KcalsW_{\text{Kcals}} \approx 2.3446 \text{ Kcals}

    The energy needed to transport the bags is approximately 2.34 Kcals\text{2.34 Kcals}.

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