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A) Identify prime numbers less than ten. Arrange them in descending order to form a number. b) Identify the second digit in the number formed in (a) and determine its total value. 2. Expand and simpli

Mathematics

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Here are the solutions to the questions:

1. a)

  1. Identify prime numbers less than ten.

    The prime numbers less than ten are $2, 3, 5, 7$.

  2. Arrange the prime numbers in descending order to form a number.

    Descending order means from largest to smallest: 7,5,3,27, 5, 3, 2.
    The number formed is 7532.

    7532\boxed{7532}

    1. b)

  3. Identify the second digit in the number formed in (a).

    The number is 7532. The second digit is 5.

  4. Determine the total value of the second digit.

    The digit 5 is in the hundreds place.
    Its total value is 5×100=5005 \times 100 = 500.

    500\boxed{500}

    2.

  5. Expand the expression by distributing the numbers outside the parentheses.

    4(q+6)+7(q−3)=(4×q)+(4×6)+(7×q)+(7×−3)4(q+6) + 7(q-3) = (4 \times q) + (4 \times 6) + (7 \times q) + (7 \times -3) =4q+24+7q−21= 4q + 24 + 7q - 21
  6. Group like terms.

    =(4q+7q)+(24−21)= (4q + 7q) + (24 - 21)
  7. Simplify the expression.

    =11q+3= 11q + 3 11q+3\boxed{11q + 3}

    3.

  8. Evaluate the product in the denominator.

    0.025×3.60.025 \times 3.6

    Multiply 25×3625 \times 36:

    25×36=90025 \times 36 = 900

    Count the total number of decimal places in 0.025 (3 places) and 3.6 (1 place). The product will have 3+1=43+1=4 decimal places.
    So, 0.025×3.6=0.0900=0.090.025 \times 3.6 = 0.0900 = 0.09.

  9. Substitute the product back into the expression.

    5.40.09\frac{5.4}{0.09}
  10. Eliminate the decimals by multiplying the numerator and denominator by a power of 10.

    To remove two decimal places from 0.09, multiply by 100.

    5.4×1000.09×100=5409\frac{5.4 \times 100}{0.09 \times 100} = \frac{540}{9}
  11. Perform the division.

    5409=60\frac{540}{9} = 60 60\boxed{60}
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