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A) Illustrate the information provided in a Venn Diagram.

Mathematics

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Here's the solution for question 11:

a) Illustrate the information provided in a Venn Diagram.

Let YY represent people who speak Yoruba, HH for Hausa, and II for Igbo.
Let the number of people in each region of the Venn diagram be as follows:

  • aa: speak Yoruba only
  • bb: speak Hausa only
  • cc: speak Igbo only
  • dd: speak Yoruba and Hausa only
  • ee: speak Yoruba and Igbo only
  • ff: speak Hausa and Igbo only
  • gg: speak all three languages (Yoruba, Hausa, and Igbo)
  • hh: speak none of the languages

Given information:
Total people = 50
g=N(Y∩H∩I)=4g = N(Y \cap H \cap I) = 4
h=N(none)=6h = N(\text{none}) = 6
Number of people who speak exactly two languages = d+e+f=14d+e+f = 14
e=12de = \frac{1}{2}d
f=d−1f = d - 1

  1. Find the values for $d, e, f$.

    Substitute the expressions for ee and ff into d+e+f=14d+e+f=14:

    d+12d+(d−1)=14d + \frac{1}{2}d + (d-1) = 14 2.5d−1=142.5d - 1 = 14 2.5d=152.5d = 15 d=152.5=6d = \frac{15}{2.5} = 6

    Now find ee and ff:

    e=12(6)=3e = \frac{1}{2}(6) = 3 f=6−1=5f = 6 - 1 = 5

    So, d=6d=6, e=3e=3, f=5f=5.

  2. Set up equations for $a, b, c$ using the total number of people.

    The sum of all regions must equal the total number of people:

    a+b+c+d+e+f+g+h=50a+b+c+d+e+f+g+h = 50

    Substitute the known values:

    a+b+c+6+3+5+4+6=50a+b+c+6+3+5+4+6 = 50 a+b+c+24=50a+b+c+24 = 50 a+b+c=26a+b+c = 26

    This means the number of people who speak one language only is 26.

  3. Express a,b,ca, b, c in terms of mm.

    Given:
    N(Y)=m2+3N(Y) = m^2+3
    N(H)=5m−3N(H) = 5m-3
    N(I)=3m+1N(I) = 3m+1
    From the Venn diagram regions:
    N(Y)=a+d+e+g=a+6+3+4=a+13N(Y) = a+d+e+g = a+6+3+4 = a+13
    N(H)=b+d+f+g=b+6+5+4=b+15N(H) = b+d+f+g = b+6+5+4 = b+15
    N(I)=c+e+f+g=c+3+5+4=c+12N(I) = c+e+f+g = c+3+5+4 = c+12
    Equating these:
    a+13=m2+3  ⟹  a=m2−10a+13 = m^2+3 \implies a = m^2-10
    b+15=5m−3  ⟹  b=5m−18b+15 = 5m-3 \implies b = 5m-18
    c+12=3m+1  ⟹  c=3m−11c+12 = 3m+1 \implies c = 3m-11

  4. Illustrate the Venn Diagram with the calculated values.

    The values for the regions are:

    • Yoruba and Hausa and Igbo (gg): 4
    • Yoruba and Hausa only (dd): 6
    • Yoruba and Igbo only (ee): 3
    • Hausa and Igbo only (ff): 5
    • None of the languages (hh): 6 The values for a,b,ca, b, c depend on mm, which will be found in part (b)(i). For the diagram, we will use the final values of a,b,ca, b, c after finding mm.

    b) Find the:

    (i) value of mm;

    (ii) number of people who speak one language only.

    (i) Value of mm.

  5. Use the equation a+b+c=26a+b+c=26 and the expressions for a,b,ca, b, c in terms of mm.

    (m2−10)+(5m−18)+(3m−11)=26(m^2-10) + (5m-18) + (3m-11) = 26 m2+8m−39=26m^2 + 8m - 39 = 26 m2+8m−65=0m^2 + 8m - 65 = 0
  6. Solve the quadratic equation for mm.

    Using the quadratic formula m=−B±B2−4AC2Am = \frac{-B \pm \sqrt{B^2 - 4AC}}{2A}:

    m=−8±82−4(1)(−65)2(1)m = \frac{-8 \pm \sqrt{8^2 - 4(1)(-65)}}{2(1)} m=−8±64+2602m = \frac{-8 \pm \sqrt{64 + 260}}{2} m=−8±3242m = \frac{-8 \pm \sqrt{324}}{2} m=−8±182m = \frac{-8 \pm 18}{2}

    Two possible values for mm:

    m1=−8+182=102=5m_1 = \frac{-8 + 18}{2} = \frac{10}{2} = 5 m2=−8−182=−262=−13m_2 = \frac{-8 - 18}{2} = \frac{-26}{2} = -13
  7. Check for valid values of mm.

    The number of people in any region cannot be negative.
    If m=5m = 5:
    a=52−10=25−10=15a = 5^2 - 10 = 25 - 10 = 15
    b=5(5)−18=25−18=7b = 5(5) - 18 = 25 - 18 = 7
    c=3(5)−11=15−11=4c = 3(5) - 11 = 15 - 11 = 4
    All these values are positive, so m=5m=5 is a valid solution.

    If $

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