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A line MN has a gradient of -2 and a y-intercept of -1. a) Write the equation of the line in the form y=mx+c. b) Generate a table of values using at least three points. c) Plot the values generated to draw the line.

Mathematics

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Answer

a

y=−2x−1y = -2x - 1

Step-by-step solution

6 steps

Huu hapa ni utatuzi wa swali lako:

Part a· 2 steps

Andika mlinganyo wa mstari katika mfumo wa y=mx+cy = mx + c.

  1. Tambua gradient na y-intercept.

    Kutoka kwa swali, tunapewa gradient (mm) ni −2-2 na y-intercept (cc) ni −1-1.

  2. Badilisha maadili haya kwenye fomula ya mlinganyo wa mstari.

    Fomula ya mlinganyo wa mstari ni y=mx+cy = mx + c.

    y=(−2)x+(−1)y = (-2)x + (-1) y=−2x−1y = -2x - 1

    Mlinganyo wa mstari ni y=−2x−1\boxed{y = -2x - 1}.

Part b· 2 steps

Tengeneza jedwali la maadili ukitumia angalau pointi tatu.

  1. Chagua maadili matatu ya xx.

    Tutatumia maadili ya x=−1,0,1x = -1, 0, 1 kama ilivyo kwenye kazi yako.

  2. Tumia mlinganyo y=−2x−1y = -2x - 1 kupata maadili yanayolingana ya yy.

    • Kwa x=−1x = -1:
    y=−2(−1)−1=2−1=1y = -2(-1) - 1 = 2 - 1 = 1
    • Kwa x=0x = 0:
    y=−2(0)−1=0−1=−1y = -2(0) - 1 = 0 - 1 = -1
    • Kwa x=1x = 1:
    y=−2(1)−1=−2−1=−3y = -2(1) - 1 = -2 - 1 = -3

    Jedwali la maadili ni:

    x−101y1−1−3\begin{array}{|c|c|c|c|} \hline x & -1 & 0 & 1 \\ \hline y & 1 & -1 & -3 \\ \hline \end{array}

Part c· 2 steps

Chora maadili yaliyotengenezwa ili kuchora mstari.

  1. Chora pointi kwenye grafu.

    Tumia jedwali la maadili kutoka sehemu (b) kuchora pointi zifuatazo kwenye grafu:

    • Pointi ya kwanza: (−1,1)(-1, 1)
    • Pointi ya pili: (0,−1)(0, -1)
    • Pointi ya tatu: (1,−3)(1, -3)
  2. Unganisha pointi kwa kutumia mstari ulionyooka.

    Baada ya kuchora pointi zote tatu, chora mstari ulionyooka unaopita kwenye pointi hizo. Mstari huu unawakilisha mlinganyo y=−2x−1y = -2x - 1.

    Mchoro wako unaonyesha pointi zimechorwa kwa usahihi. Hatua inayofuata ni kuunganisha pointi hizo kwa mstari ulionyooka.

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