A person makes deposits into a savings account. The deposits form an arithmetic progression. The 4th deposit is 150,000 FCFA and the 6th deposit is 250,000 FCFA. Find the first deposit and the common

May 5, 2026Mathematics

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May 5, 2026

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150,000 \text{ FCFA}$$

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Question 17: This is an arithmetic progression problem. Step 1: Identify the given terms in the arithmetic progression (AP). We are given the $4^{th}$ deposit ( $a_4$ ) and the $6^{th}$ deposit ( $a_6$ ). $a_4 = 150\,000 \text{ FCFA}$ $a_6 = 250\,000 \text{ FCFA}$ Step 2: Use the formula for the $n^{th}$ term of an AP, $a_n = a_1 + (n-1)d$ , where $d$ is the common difference. For $a_4$ :

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Question 17: This is an arithmetic progression problem. Step 1: Identify the given terms in the arithmetic progression (AP).

Asked on May 5, 2026Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI AnswerAnswered on May 5, 2026

Here are the solutions to your questions: Question 17: This is an arithmetic progression problem. Step 1: Identify the given terms in the arithmetic progression (AP). We are given the 4^th deposit (a_4) and the 6^th deposit (a_6). a_4 = 150\,000 FCFA a_6 = 250\,000 FCFA Step 2: Use the formula for the n^th term of an AP, a_n = a_1 + (n-1)d, where d is the common difference. For a_4: