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A pie chart shows the total livestock population in millions. If buffalo comprise 20.45% and beef cattle comprise 24.9% of the total 34.736 million livestock, with cattle making up 35.94% of the total

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3 parts
3.1

7.104 million\text{7.104 million}

3.3
0.693
3.5

40.200 million\text{40.200 million}

Step-by-step solution

9 steps

here are the answers to Question 3:

Part 3.1· 3 steps

  1. Identify the total livestock population from the pie chart.

    Total livestock population = 34.736 million.

  2. Identify the percentage of buffalo from the pie chart.

    Percentage of buffalo = 20.45%20.45\%.

  3. Calculate the actual number of the buffalo population.

    Buffalo population=Total livestock population×Percentage of buffalo100\text{Buffalo population} = \text{Total livestock population} \times \frac{\text{Percentage of buffalo}}{100} Buffalo population=34.736 million×20.45100\text{Buffalo population} = 34.736 \text{ million} \times \frac{20.45}{100} Buffalo population=34.736×0.2045\text{Buffalo population} = 34.736 \times 0.2045 Buffalo population=7.103992 million\text{Buffalo population} = 7.103992 \text{ million}

    Rounding to three decimal places:

    Buffalo population≈7.104 million\text{Buffalo population} \approx 7.104 \text{ million}

    The actual number of the buffalo population is 7.104 million\boxed{\text{7.104 million}}.

Part 3.2

An example of livestock that can be classified as OTHER is chickens (or poultry).

Part 3.30.693

  1. Identify the percentage of beef cattle from the pie chart.

    Percentage of beef cattle = 24.9%24.9\%.

  2. Identify the total percentage of cattle from the pie chart.

    Total percentage of cattle = 35.94%35.94\%.

  3. Determine the probability of randomly selecting beef cattle from the percentage cattle livestock population.

    Probability=Percentage of beef cattleTotal percentage of cattle\text{Probability} = \frac{\text{Percentage of beef cattle}}{\text{Total percentage of cattle}} Probability=24.935.94\text{Probability} = \frac{24.9}{35.94} Probability≈0.69282\text{Probability} \approx 0.69282

    Rounding to three decimal places:

    Probability≈0.693\text{Probability} \approx 0.693

    The probability is 0.693\boxed{0.693}.

Part 3.4

This is a statement providing information for the next question.

Part 3.5

40.200 million\text{40.200 million}

  1. Identify the total livestock population in November 2019.

    Total livestock population in November 2019 = 34.736 million.

  2. Identify the percentage increase between November 2019 and November 2020.

    Percentage increase = 15.7%15.7\%.

  3. Calculate the total livestock population in November 2020.

    Population in 2020=Population in 2019×(1+Percentage increase100)\text{Population in 2020} = \text{Population in 2019} \times \left(1 + \frac{\text{Percentage increase}}{100}\right) Population in 2020=34.736 million×(1+15.7100)\text{Population in 2020} = 34.736 \text{ million} \times \left(1 + \frac{15.7}{100}\right) Population in 2020=34.736 million×(1+0.157)\text{Population in 2020} = 34.736 \text{ million} \times (1 + 0.157) Population in 2020=34.736 million×1.157\text{Population in 2020} = 34.736 \text{ million} \times 1.157 Population in 2020=40.199952 million\text{Population in 2020} = 40.199952 \text{ million}

    Rounding to three decimal places:

    Population in 2020≈40.200 million\text{Population in 2020} \approx 40.200 \text{ million}

    The total livestock population in November 2020 is 40.200 million\boxed{\text{40.200 million}}.

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