This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
ScanSolve AI Answer
Step 1: State the assumed scale for the plan. For questions 2.3 (a) and (b), it is assumed that the plan uses Scale D, which is a ratio scale of 1 : 200. This means 1 cm on the plan represents 200 cm in actual distance. Step 2: Calculate the actual dimensions of the Classroom for 2.3 (a). Given: Classroom Length on Plan = 3,5 cm Classroom Width on Plan = 2,5 cm Scale Denominator = 200 Actual Length = Plan Length × Scale Denominator Actual Length = 3,5 cm × 200 = 700 cm Convert to meters (1 m = 100 cm): Actual Length = 700 cm100 = 7 m Actual Width = Plan Width × Scale Denominator Actual Width = 2,5 cm × 200 = 500 cm Convert to meters: Actual Width = 500 cm100 = 5 m 2.3 a) Actual Length = 7 m 2.3 a) Actual Width = 5 m Step 3: Calculate the actual floor area of the Computer Lab for 2.3 (b). Given: Computer Lab Length on Plan = 4,0 cm Computer Lab Width on Plan = 3,0 cm Scale Denominator = 200 First, calculate the actual length and width in meters: Actual Length = Plan Length × Scale Denominator Actual Length = 4,0 cm × 200 = 800 cm Convert to meters: Actual Length = 800 cm100 = 8 m Actual Width = Plan Width × Scale Denominator Actual Width = 3,0 cm × 200 = 600 cm Convert to meters: Actual Width = 600 cm100 = 6 m Now, calculate the actual floor area: Actual Floor Area = Actual Length × Actual Width Actual Floor Area = 8 m × 6 m = 48 m^2 2.3 b) Actual floor area = 48 m^2 Step 4: Address Question 3. The image provided only shows the title "QUESTION 3 CALCULATING MAP DISTANCE & DETERMINING THE SCALE" and a key formula. There are no specific sub-questions or tasks to solve under Question 3 in this image. Last free one today — make it count tomorrow, or type /upgrade for unlimited.