A Sociologist collected a sample of eight house and recorded the number of children in each house hold. The numbers are as follows: 2, 4, 3, 5, 1, 4, 3, 2. Find the Sample mean, mean deviation, Sample variency and the Sample standard deviation.

The formula for the sample mean is $\bar{x} = \frac{\sum x_i}{n}$.

$$\sum x_i = 2 + 4 + 3 + 5 + 1 + 4 + 3 + 2 = 24$$ $$\bar{x} = \frac{24}{8} = 3$$

The sample mean is $\boxed{\text{3}}$.

The formula for the mean deviation is $MD = \frac{\sum |x_i - \bar{x}|}{n}$.
First, find the absolute differences from the mean:
$|2 - 3| = 1$
$|4 - 3| = 1$
$|3 - 3| = 0$
$|5 - 3| = 2$
$|1 - 3| = 2$
$|4 - 3| = 1$
$|3 - 3| = 0$
$|2 - 3| = 1$

$$\sum |x_i - \bar{x}| = 1 + 1 + 0 + 2 + 2 + 1 + 0 + 1 = 8$$ $$MD = \frac{8}{8} = 1$$

The mean deviation is $\boxed{\text{1}}$.

The formula for the sample variance is $s^2 = \frac{\sum (x_i - \bar{x})^2}{n-1}$.
First, find the squared differences from the mean:
$(2 - 3)^2 = (-1)^2 = 1$
$(4 - 3)^2 = (1)^2 = 1$
$(3 - 3)^2 = (0)^2 = 0$
$(5 - 3)^2 = (2)^2 = 4$
$(1 - 3)^2 = (-2)^2 = 4$
$(4 - 3)^2 = (1)^2 = 1$
$(3 - 3)^2 = (0)^2 = 0$
$(2 - 3)^2 = (-1)^2 = 1$

$$\sum (x_i - \bar{x})^2 = 1 + 1 + 0 + 4 + 4 + 1 + 0 + 1 = 12$$ $$s^2 = \frac{12}{8-1} = \frac{12}{7} \approx 1.714$$

The sample variance is $\boxed{\frac{12}{7} \approx 1.714}$.

The formula for the sample standard deviation is $s = \sqrt{s^2}$.

$$s = \sqrt{\frac{12}{7}} \approx \sqrt{1.7142857} \approx 1.309$$

The sample standard deviation is $\boxed{\sqrt{\frac{12}{7}} \approx 1.309}$.