A surveyor is measuring the width of a pond. She chooses a landmark on the opposite side of the pond, and measures the angle to this landmark from a point 50 feet away from the original point. How wide is the pond to the nearest ft?

The problem describes a right-angled triangle ABC, where the right angle is at B.
The length of side BC is given as $50 \text{ ft}$.
The width of the pond is represented by the side AB.
From the faint writing on the image, we assume the angle $\angle BCA = 70^\circ$.

In a right-angled triangle, the tangent of an angle is the ratio of the length of the opposite side to the length of the adjacent side.
For angle C, the opposite side is AB and the adjacent side is BC.

We have $\angle BCA = 70^\circ$ and $BC = 50 \text{ ft}$.

Multiply both sides by 50 to find AB.

Using a calculator for $\tan(70^\circ)$:

Rounding to the nearest foot:

The width of the pond is approximately 137 ft.

The width of the pond is $\text{137 ft}$.