A toy is in the form of a hemisphere surmounted by a cone. The height of the cone is 2 cm and the diameter of its base is 4 cm. Find the volume of the toy. Use pi = 22/7.

The toy consists of a hemisphere surmounted by a cone.
Height of the cone ($h$) = 2 cm.
Diameter of the base = 4 cm.
Radius ($r$) = $\frac{\text{diameter}}{2} = \frac{4 \text{ cm}}{2} = 2$ cm.
We are given to use $\pi = \frac{22}{7}$.

The total volume of the toy is the sum of the volume of the hemisphere and the volume of the cone.
Volume of hemisphere ($V_{hemisphere}$) = $\frac{2}{3} \pi r^3$
Volume of cone ($V_{cone}$) = $\frac{1}{3} \pi r^2 h$

Calculate $V_{hemisphere}$:

Calculate $V_{cone}$:

Calculate the total volume ($V_{toy}$):

Simplify the fraction by dividing numerator and denominator by 3:

The volume of the toy is $\boxed{\frac{176}{7} \text{ cm}^3}$.

The total surface area of the toy is the sum of the curved surface area of the hemisphere and the curved surface area of the cone.
Curved surface area of hemisphere ($CSA_{hemisphere}$) = $2 \pi r^2$
Curved surface area of cone ($CSA_{cone}$) = $\pi r l$, where $l$ is the slant height of the cone.

First, calculate the slant height ($l$) of the cone:

Calculate $CSA_{hemisphere}$:

Calculate $CSA_{cone}$:

Calculate the total surface area ($SA_{toy}$):

Factor out 88 from the numerator:

The surface area of the toy is $\boxed{\frac{88(2 + \sqrt{2})}{7} \text{ cm}^2}$.