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A translation maps a point (1,2) onto (-1,2). What would be the coordinates of the object whose image is (-3,-3) under the same translation?

Mathematics

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(-1,-3)

Haya hapa masuluhisho ya maswali uliyotoa:

A translation maps a point (1,2)(1,2) onto (−1,2)(-1,2). What would be the coordinates of the object whose image is (−3,−3)(-3,-3) under the same translation?

  • Step 1: Determine the translation vector. Let the translation vector be T=(ab)T = \begin{pmatrix} a \\ b \end{pmatrix}. A point (x,y)(x,y) is translated to its image (x′,y′)(x',y') by the rule:

    (x′y′)=(xy)+(ab)\begin{pmatrix} x' \\ y' \end{pmatrix} = \begin{pmatrix} x \\ y \end{pmatrix} + \begin{pmatrix} a \\ b \end{pmatrix}

    Given that the point (1,2)(1,2) is mapped onto (−1,2)(-1,2):

    (−12)=(12)+(ab)\begin{pmatrix} -1 \\ 2 \end{pmatrix} = \begin{pmatrix} 1 \\ 2 \end{pmatrix} + \begin{pmatrix} a \\ b \end{pmatrix}

    From the x-coordinates: −1=1+a  ⟹  a=−1−1=−2-1 = 1 + a \implies a = -1 - 1 = -2. From the y-coordinates: 2=2+b  ⟹  b=2−2=02 = 2 + b \implies b = 2 - 2 = 0. So, the translation vector is T=(−20)T = \begin{pmatrix} -2 \\ 0 \end{pmatrix}.

  • Step 2: Find the coordinates of the object. Let the object's coordinates be (xo,yo)(x_o, y_o). Its image is given as (−3,−3)(-3,-3). Using the same translation vector:

    (−3−3)=(xoyo)+(−20)\begin{pmatrix} -3 \\ -3 \end{pmatrix} = \begin{pmatrix} x_o \\ y_o \end{pmatrix} + \begin{pmatrix} -2 \\ 0 \end{pmatrix}

    From the x-coordinates: −3=xo−2  ⟹  xo=−3+2=−1-3 = x_o - 2 \implies x_o = -3 + 2 = -1. From the y-coordinates: −3=yo+0  ⟹  yo=−3-3 = y_o + 0 \implies y_o = -3. The coordinates of the object are (−1,−3)(-1,-3).

The coordinates of the object are (−1,−3)\boxed{(-1,-3)}.

17. A bag contains 8 red balls and 6 blue balls all identical in size and shape. Jane selected 3 balls at random without replacement.

(a) Draw a tree diagram to represent this information.

  • Step 1: Identify initial probabilities. Total number of balls = 8 Red + 6 Blue = 14 balls. Probability of drawing a Red ball first (R1) = 814\frac{8}{14} Probability of drawing a Blue ball first (B1) = 614\frac{6}{14}

  • Step 2: Draw the tree diagram for three selections without replacement.

                                      Start
                                        |
             ___________________________|___________________________
            /                                                       \
           /                                                         \
      (8/14) R1                                                 (6/14) B1
         /                                                           \
        /                                                             \
       /                                                               \
      /                                                                 \
     /                                                                   \
    /___________________________                                  ___________________________\
   /                             \                               /                             \
  /                               \                             /                               \
(7/13) R2                       (6/13) B2                   (8/13) R2                       (5/13) B2
 /       \                       /       \                   /       \                       /       \
/         \                     /         \                 /         \                     /         \
R3 (6/12) B3 (6/12)           R3 (7/12) B3 (5/12)         R3 (7/12) B3 (5/12)           R3 (8/12) B3 (4/12)
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