A water bucket is cylindrical in shape. The diameter of the bucket is 40 cm. The bucket is filled with water up to a height of 42 cm. What is the surface area of the bucket in contact with water? (Use calculator value for π)

Comparing with the options, the closest value is 1.14 m.
The final answer is $\boxed{\text{B. 1.14 m}}$.

Diameter $D = 40 \text{ cm}$, so radius $r = \frac{40}{2} = 20 \text{ cm}$.
Base area $A_{base} = \pi r^2 = \pi (20 \text{ cm})^2 = 400\pi \text{ cm}^2$.

Height of water $h = 42 \text{ cm}$.
Lateral surface area $A_{lateral} = 2\pi r h = 2\pi (20 \text{ cm})(42 \text{ cm}) = 1680\pi \text{ cm}^2$.

Using a calculator value for $\pi \approx 3.14159$:

Comparing with the options, the closest value is 6534.51.
The final answer is $\boxed{\text{C. 6534.51}}$.

Length $l = 8.5 \text{ cm}$, width $w = 5 \text{ cm}$, height $h = 13 \text{ cm}$.

Since $1 \text{ litre} = 1000 \text{ cm}^3$:

Comparing with the options, the closest value is 0.51 litres (there might be a slight discrepancy in the question's options or values, but 0.5525 is closest to 0.51 among the given choices, assuming rounding or slight approximation). Let's recheck the calculation.
$8.5 \times 5 = 42.5$
$42.5 \times 13 = 552.5$
So, 0.5525 litres is the correct calculation. Option A is 0.51 litres. This is the closest.

Let's re-evaluate the options and the calculated value.
A. 0.51 litres
B. 5.1 litres
C. 510 litres
D. 510000 litres

My calculated value is 0.5525 litres. Option A is 0.51 litres. This is the closest. It's possible the question intended slightly different dimensions or expects rounding. Given the options, A is the most plausible.

The final answer is $\boxed{\text{A. 0.51 litres}}$.