Calculate the angle in radians and degrees, and the area of the sector, given an arc length of 10 cm and a radius of 4 cm.

The formula for arc length $s$ is $s = r\theta$, where $r$ is the radius and $\theta$ is the angle in radians.
Given $s = 10 \text{ cm}$ and $r = 4 \text{ cm}$.

$$10 = 4\theta$$ $$\theta = \frac{10}{4}$$ $$\theta = \frac{5}{2} \text{ radians}$$ $$\theta = 2.5 \text{ radians}$$

To convert radians to degrees, multiply by $\frac{180^\circ}{\pi}$.

$$\theta_{\text{degrees}} = \frac{5}{2} \times \frac{180^\circ}{\pi}$$ $$\theta_{\text{degrees}} = \frac{450^\circ}{\pi}$$

Using $\pi \approx 3.14159$:

$$\theta_{\text{degrees}} \approx \frac{450^\circ}{3.14159}$$ $$\theta_{\text{degrees}} \approx 143.239^\circ$$

The formula for the area of a sector $A$ is $A = \frac{1}{2}r^2\theta$, where $\theta$ is in radians.
Given $r = 4 \text{ cm}$ and $\theta = \frac{5}{2} \text{ radians}$.

$$A = \frac{1}{2}(4 \text{ cm})^2 \left(\frac{5}{2}\right)$$ $$A = \frac{1}{2}(16 \text{ cm}^2) \left(\frac{5}{2}\right)$$ $$A = 8 \text{ cm}^2 \times \frac{5}{2}$$ $$A = 4 \text{ cm}^2 \times 5$$ $$A = 20 \text{ cm}^2$$

The angle subtended by the arc is $\boxed{\text{2.5 radians}}$ or $\boxed{\frac{450}{\pi} \text{ degrees}}$.
The area of the corresponding sector is $\boxed{\text{20 cm}^2}$.