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Answer the whole of this question on a sheet of graph paper. Use a scale of 2cm to 1 unit on the x axis and 2cm to 5 units on the y axis. The table below is for values of the function y = 6x − x2 − x3.

Mathematics

ScanSolve AI Answer

Graph of y = 6x − x² − x³

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Key points of y = 6x − x² − x³
Pointxy
x-intercept−30
Minimum−1.79−8.21
x-intercept00
Maximum1.124.06
x-intercept20

Step-by-step solution

5 steps

Here's the solution for question 10(b):

b) (i)
The gradient of a slope is given by the tangent of its angle of inclination with the horizontal.
The slope AC is inclined to the horizontal ground AH at 15∘15^\circ.

  1. Identify the angle of inclination.

    The angle of inclination is θ=15∘\theta = 15^\circ.

  2. Calculate the gradient using the tangent function.

    Gradient=tan⁡(θ)=tan⁡(15∘)\text{Gradient} = \tan(\theta) = \tan(15^\circ) Gradient≈0.267949...\text{Gradient} \approx 0.267949...
  3. Round the answer to 2 decimal places.

    Gradient≈0.27\text{Gradient} \approx \boxed{0.27}

    b) (ii)
    We need to calculate ∠APB\angle APB.
    The problem states that BP is a post standing on the sloping ground AC. In geometry, a post standing on the ground is typically assumed to be perpendicular to the ground unless stated otherwise. The diagram also shows a right-angle symbol at P, indicating that BP is perpendicular to AC.

  4. Identify the relationship between BP and AC.

    BP is perpendicular to AC.

  5. Determine the angle ∠APB\angle APB.

    Since BP is perpendicular to AC, the angle formed at their intersection P is 90∘90^\circ.

    ∠APB=90∘\angle APB = \boxed{90^\circ}
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