Find the antilogarithms of the following numbers: a) 0.3760 b) 0.7783 c) 1.6415 d) 1.1127 e) 1.9364 f) 2.8579 g) 2.8835 h) 3.5104 i) 1.8056 j) 0.5467

$$10^{0.3760} \approx 2.377$$

The number is $\boxed{2.377}$.

$$10^{0.7783} \approx 6.003$$

The number is $\boxed{6.003}$.

$$10^{1.6415} \approx 43.80$$

The number is $\boxed{43.80}$.

$$10^{1.1127} \approx 13.05$$

The number is $\boxed{13.05}$.

$$10^{1.9364} \approx 86.39$$

The number is $\boxed{86.39}$.

$$10^{2.8579} \approx 721.0$$

The number is $\boxed{721.0}$.

$$10^{2.8835} \approx 764.7$$

The number is $\boxed{764.7}$.

$$10^{3.5104} \approx 3239$$

The number is $\boxed{3239}$.

$$10^{-1 + 0.8056} = 10^{0.8056} \times 10^{-1} \approx 6.392 \times 10^{-1} = 0.6392$$

The number is $\boxed{0.6392}$.

j) For $\bar{1}.7194$:

$$10^{-1 + 0.7194} = 10^{0.7194} \times 10^{-1} \approx 5.241 \times 10^{-1} = 0.5241$$

The number is $\boxed{0.5241}$.

k) For $\bar{2}.5518$:

$$10^{-2 + 0.5518} = 10^{0.5518} \times 10^{-2} \approx 3.563 \times 10^{-2} = 0.03563$$

The number is $\boxed{0.03563}$.

l) For $\bar{3}.2052$:

$$10^{-3 + 0.2052} = 10^{0.2052} \times 10^{-3} \approx 1.604 \times 10^{-3} = 0.001604$$

The number is $\boxed{0.001604}$.