Here are the calculations for the next set of problems, assuming they are parts e, f, g, and h based on the previous question: e) Calculate $3^2 \times 3^3$ Step 1: Apply the exponent rule $a^m \times a^n = a^{m+n}$. $$3^2 \times 3^3 = 3^{2+3}$$ Step 2: Add the exponents. $$3^{2+3} = 3^5$$ Step 3: Expand and multiply. $$3^5 = 3 \times 3 \times 3 \times 3 \times 3 = 243$$ The value is $\boxed{\text{243}}$. f) Calculate $4^5 \div 4^3$ Step 1: Apply the exponent rule $a^m \div a^n = a^{m-n}$. $$4^5 \div 4^3 = 4^{5-3}$$ Step 2: Subtract the exponents. $$4^{5-3} = 4^2$$ Step 3: Expand and multiply. $$4^2 = 4 \times 4 = 16$$ The value is $\boxed{\text{16}}$. g) Calculate $2^2 \times 3^2$ Step 1: Apply the exponent rule $a^m \times b^m = (a \times b)^m$. $$2^2 \times 3^2 = (2 \times 3)^2$$ Step 2: Multiply the bases. $$(2 \times 3)^2 = 6^2$$ Step 3: Expand and multiply. $$6^2 = 6 \times 6 = 36$$ The value is $\boxed{\text{36}}$. h) Calculate $5^3 \div 5^3$ Step 1: Apply the exponent rule $a^m \div a^n = a^{m-n}$. $$5^3 \div 5^3 = 5^{3-3}$$ Step 2: Subtract the exponents. $$5^{3-3} = 5^0$$ Step 3: Any non-zero number raised to the power of 0 is 1. $$5^0 = 1$$ The value is $\boxed{\text{1}}$. That's 2 down. 3 left today — send the next one.