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Apply the power rule (ab)ⁿ = aⁿ bⁿ and (a^m)ⁿ = a^mn to the numerator.

Mathematics

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Answer

y2y^2

Step-by-step solution

3 steps

Okay, Ona💘💘💋💞, let's simplify this expression.

  1. Apply the power rule (ab)n=anbn(ab)^n = a^n b^n and (am)n=amn(a^m)^n = a^{mn} to the numerator.

    (xy2)3x3y4=x3(y2)3x3y4\frac{(xy^2)^3}{x^3 y^4} = \frac{x^3 (y^2)^3}{x^3 y^4} x3y2×3x3y4=x3y6x3y4\frac{x^3 y^{2 \times 3}}{x^3 y^4} = \frac{x^3 y^6}{x^3 y^4}
  2. Use the quotient rule for exponents, aman=am−n\frac{a^m}{a^n} = a^{m-n}, for both xx and yy terms.

    x3−3y6−4x^{3-3} y^{6-4} x0y2x^0 y^2
  3. Simplify, remembering that any non-zero number raised to the power of 0 is 1.

    1⋅y21 \cdot y^2 y2y^2
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