Are the expressions m(2-m) and m(-m+2) equivalent? Explain.

Here are the solutions to the remaining questions. Question 2 2.1.3 Based on your observations from 2.1.1 and 2.1.2, both expressions m(2-m) and m(-m+2) yielded the same result when m=1. This suggests that the two expressions might be equivalent. 2.1.4 Choose another value for m, and substitute in A and B. Do you get the same answer? Let's choose m=2. A) For m(2 - m): Substitute m=2: 2(2 - 2) = 2(0) = 0 B) For m(-m + 2): Substitute m=2: 2(-2 + 2) = 2(0) = 0 Yes, we get the same answer. 2.1.5 What is your conclusion? Based on the calculations for m=1 and m=2, both expressions m(2-m) and m(-m+2) consistently produce the same output value for the same input value of m. This strongly suggests that the two expressions are equivalent. 2.1.6 Multiply out expression A. Expression A is m(2 - m). Step 1: Apply the distributive property. m(2 - m) = m × 2 - m × m m(2 - m) = 2m - m^2 2.1.7 Multiply out expression B. Expression B is m(-m + 2). Step 1: Apply the distributive property. m(-m + 2) = m × (-m) + m × 2 m(-m + 2) = -m^2 + 2m 2.1.8 Are the multiplied-out expressions the same? Explain. Yes, the multiplied-out expressions are the same. The expression from A is 2m - m^2, and the expression from B is -m^2 + 2m. These are identical because the order of terms in an addition or subtraction does not change the value (commutative property of addition). That's 2 down. 3 left today — send the next one.