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Calculate the area of a rectangle with sides 3007m and 2993m, and evaluate 250092 and 2032 using algebraic identities.
Mathematics
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12 stepsHere are the solutions to the problems:
- a) To find the area of a rectangular piece of land with dimensions by , we use the identity .
Express the dimensions in the form and .
$$ 3007 = 3000 + 7 $$ $$ 2993 = 3000 - 7 $$ So, $a = 3000$ and $b = 7$.Apply the identity.
$$ \text{Area} = (3000 + 7)(3000 - 7) = 3000^2 - 7^2 $$Calculate the squares.
$$ 3000^2 = 9000000 $$ $$ 7^2 = 49 $$Subtract the values.
$$ \text{Area} = 9000000 - 49 = 8999951 $$ The area is $\boxed{\text{8999951 m}^2}$.2. b) To evaluate , we use the identity .
Express 25009 in the form .
$$ 25009 = 25000 + 9 $$ So, $a = 25000$ and $b = 9$.Apply the identity.
$$ 25009^2 = (25000 + 9)^2 = 25000^2 + 2(25000)(9) + 9^2 $$Calculate each term.
$$ 25000^2 = 625000000 $$ $$ 2(25000)(9) = 50000 \times 9 = 450000 $$ $$ 9^2 = 81 $$Add the terms.
$$ 25009^2 = 625000000 + 450000 + 81 = 625450081 $$ The value is $\boxed{625450081}$.3. c) To find the area of a square marrow with dimensions , we use the identity .
Express 203 in the form .
$$ 203 = 200 + 3 $$ So, $a = 200$ and $b = 3$.Apply the identity.
$$ \text{Area} = 203^2 = (200 + 3)^2 = 200^2 + 2(200)(3) + 3^2 $$Calculate each term.
$$ 200^2 = 40000 $$ $$ 2(200)(3) = 400 \times 3 = 1200 $$ $$ 3^2 = 9 $$Add the terms.
$$ \text{Area} = 40000 + 1200 + 9 = 41209 $$ The area is $\boxed{\text{41209 cm}^2}$.
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