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b) The 6 faces of a solid cube of length 3 m is to be painted. The painting cost is ksh 150 per square metre. Find the total cost of painting the cube.

Mathematics

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Answer

b

Ksh 8100\text{Ksh 8100}

Step-by-step solution

3 steps

Haya Mercy, twende kazi.

Part a

Calculate the perimeter of the following sector. (π=3.142\pi = 3.142)

Samahani, picha haionyeshi sekta inayohitajika kukokotoa mzingo wake. Tafadhali tuma picha kamili ya swali hili.

Part b

Ksh 8100\text{Ksh 8100}

The 6 faces of a solid cube of length 3m is to be painted. The painting cost is Ksh 150 per square metre. Find the total cost of painting the cube.

  1. Kokotoa eneo la uso mmoja wa mchemraba.

    Urefu wa upande wa mchemraba (ss) ni 3 m.
    Eneo la uso mmoja = s2=(3 m)2=9 m2s^2 = (3 \text{ m})^2 = 9 \text{ m}^2.

  2. Kokotoa jumla ya eneo la nyuso zote za mchemraba.

    Mchemraba una nyuso 6.
    Jumla ya eneo la nyuso = 6×Eneo la uso mmoja6 \times \text{Eneo la uso mmoja}
    Jumla ya eneo la nyuso = 6×9 m2=54 m26 \times 9 \text{ m}^2 = 54 \text{ m}^2.

  3. Kokotoa gharama yote ya kupaka rangi mchemraba.

    Gharama ya kupaka rangi kwa kila mita ya mraba ni Ksh 150.
    Jumla ya gharama = Jumla ya eneo la nyuso ×\times Gharama kwa kila mita ya mraba
    Jumla ya gharama = 54 m2×Ksh 150/m254 \text{ m}^2 \times \text{Ksh } 150/\text{m}^2
    Jumla ya gharama = Ksh 8100\text{Ksh } 8100.
    Jumla ya gharama ya kupaka rangi mchemraba ni Ksh 8100\boxed{\text{Ksh 8100}}.

Part c

Identify the greater ratio by expressing the two ratios into percentage.

Samahani, picha haionyeshi uwiano (ratios) unaohitajika kulinganishwa. Tafadhali tuma picha kamili ya swali hili.

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