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Campers have enough food to last 56 of them days. How long would the job take? 3. IF 3kg of beef costs P36, find the cost of a) 11kg

Mathematics

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The problem describes an inverse proportion between the number of men and the number of days the food lasts (or a job takes). The table provides the specific values.

  1. Identify the given values and the relationship.

    Initially, there are 12 men, and the job takes 9 days.
    For the new scenario, there are 5 men, and we need to find the number of days, let's call it xx.
    Since the total amount of work (or food supply) is constant, the product of men and days remains the same.

  2. Set up the inverse proportion equation.

    M1×D1=M2×D2M_1 \times D_1 = M_2 \times D_2 12 men×9 days=5 men×x days12 \text{ men} \times 9 \text{ days} = 5 \text{ men} \times x \text{ days}
  3. Solve for xx.

    108=5x108 = 5x x=1085x = \frac{108}{5} x=21.6x = 21.6

    The job would take 21.6 days for 5 men.

    The job would take 21.6 days\boxed{\text{21.6 days}}.

    :
    This problem describes a direct proportion between the mass of beef and its cost.

  4. Identify the given values and the relationship.

    3 kg of beef costs P36P36. We need to find the cost of 11 kg of beef.
    The cost per kilogram is constant.

  5. Calculate the cost per kilogram.

    Cost per kg=Total CostTotal Mass\text{Cost per kg} = \frac{\text{Total Cost}}{\text{Total Mass}} Cost per kg=P363 kg\text{Cost per kg} = \frac{P36}{3 \text{ kg}} Cost per kg=P12/kg\text{Cost per kg} = P12/\text{kg}
  6. Calculate the cost of 11 kg of beef.

    Cost of 11 kg=Cost per kg×11 kg\text{Cost of 11 kg} = \text{Cost per kg} \times 11 \text{ kg} Cost of 11 kg=P12/kg×11 kg\text{Cost of 11 kg} = P12/\text{kg} \times 11 \text{ kg} Cost of 11 kg=P132\text{Cost of 11 kg} = P132

    The cost of 11 kg of beef is P132\boxed{P132}.

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