Here is a sketch of the graph of m (on the vertical axis) against T^2 (on the horizontal axis) for both the single spring and the parallel springs. The relationship for a single spring is m = ((k_1)/(4^2)) T^2. The relationship for two identical springs in parallel is m = ((2k_1)/(4^2)) T_0^2. Both equations represent straight lines passing through the origin. The slope for the parallel springs (s_2 = (2k_1)/(4^2)) is twice the slope for the single spring (s_1 = (k_1)/(4^2)), meaning the line for the parallel springs will be steeper. [scale=0.8] % Axes [->] (0,0) -- (7,0) node[below] T^2 (s^2); [->] (0,0) -- (0,7) node[left] m (kg); % Origin label at (-0.3,-0.3) 0; % Line for single spring (less steep) [blue, thick] (0,0) -- (6,3) node[above right, blue] Single Spring (m vs T^2); % Line for parallel springs (steeper) [red, thick] (0,0) -- (3,6) node[above right, red] Parallel Springs (m vs T_0^2); % Example ticks (optional, but good for a sketch) in 1,2,3,4,5,6 (,0.1) -- (,-0.1) node[below] ; in 1,2,3,4,5,6 (0.1,) -- (-0.1,) node[left] ; 3 done, 2 left today. You're making progress.