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Which colours on the spinner are equally likely to be landed on? Give a reason for your answer.

Mathematics

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Answers

4 parts
a

14\frac{1}{4}

b
0
c

25\frac{2}{5}

d

720\frac{7}{20}

Step-by-step solution

11 steps

Here are the answers to questions 5 and 6, based on the spinner results from the previous table.

5. Which colours on the spinner are equally likely to be landed on? Give a reason for your answer.

Based on the 20 spins:

  • Yellow: 5 times
  • Green: 7 times
  • Blue: 8 times
  • Red: 0 times

No colors were equally likely to be landed on.
Reason: The number of times each color appeared in the 20 spins was different.

6. What is the probability of a spinner landing on:

The total number of spins is 20. The probability of an event is calculated as:

P(event)=Number of times the event occurredTotal number of trialsP(\text{event}) = \frac{\text{Number of times the event occurred}}{\text{Total number of trials}}

Part a· 3 steps

yellow?

  1. Identify the number of yellow outcomes.

    Yellow occurred 5 times.

  2. Calculate the probability.

    P(yellow)=520P(\text{yellow}) = \frac{5}{20}
  3. Simplify the fraction.

    P(yellow)=14P(\text{yellow}) = \frac{1}{4}

    The probability of landing on yellow is 14\boxed{\frac{1}{4}}.

Part b0

red?

  1. Identify the number of red outcomes.

    Red occurred 0 times.

  2. Calculate the probability.

    P(red)=020P(\text{red}) = \frac{0}{20}
  3. Simplify the fraction.

    P(red)=0P(\text{red}) = 0

    The probability of landing on red is 0\boxed{0}.

Part c

25\frac{2}{5}

blue?

  1. Identify the number of blue outcomes.

    Blue occurred 8 times.

  2. Calculate the probability.

    P(blue)=820P(\text{blue}) = \frac{8}{20}
  3. Simplify the fraction.

    P(blue)=25P(\text{blue}) = \frac{2}{5}

    The probability of landing on blue is 25\boxed{\frac{2}{5}}.

Part d

720\frac{7}{20}

green?

  1. Identify the number of green outcomes.

    Green occurred 7 times.

  2. Calculate the probability.

    P(green)=720P(\text{green}) = \frac{7}{20}

    The probability of landing on green is 720\boxed{\frac{7}{20}}.

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