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Concrete blocks of length 14/25 m were laid end to end along the four sides of a rectangular lawn 28 m long and 21 m wide. How many blocks were required to complete one layer?

Mathematics

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2 parts
b

The distance increases to 480 km, an increase of 60 km.\text{The distance increases to } 480 \text{ km, an increase of } 60 \text{ km.}

a

175 blocks175 \text{ blocks}

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here are the solutions to the remaining questions.

Part 2

Part b

The distance increases to 480 km, an increase of 60 km.\text{The distance increases to } 480 \text{ km, an increase of } 60 \text{ km.}

If the speed of X is increased by 20 km/h within the 3 hours, what would be the effect on the distance between X and Y?

  1. Calculate the new speed of car X.

    Original speed of X, SX=60 km/hS_X = 60 \text{ km/h}.
    Increased speed of X, SX′=60+20=80 km/hS'_X = 60 + 20 = 80 \text{ km/h}.
    Speed of Y, SY=80 km/hS_Y = 80 \text{ km/h}.
    Time, t=3 hourst = 3 \text{ hours}.

  2. Calculate the new relative speed of the two cars.

    Since they are traveling in opposite directions, their speeds add up.
    New relative speed, Srelative′=SX′+SYS'_{relative} = S'_X + S_Y

    Srelative′=80 km/h+80 km/h=160 km/hS'_{relative} = 80 \text{ km/h} + 80 \text{ km/h} = 160 \text{ km/h}
  3. Calculate the new total distance apart.

    New distance apart =Srelative′×t= S'_{relative} \times t

    New distance apart=160 km/h×3 hours\text{New distance apart} = 160 \text{ km/h} \times 3 \text{ hours} New distance apart=480 km\text{New distance apart} = 480 \text{ km}

    The original distance was 420 km. The new distance is 480 km.
    The effect is that the distance between X and Y will increase by 480−420=60 km480 - 420 = 60 \text{ km}.

    The distance increases to 480 km, an increase of 60 km.\boxed{\text{The distance increases to } 480 \text{ km, an increase of } 60 \text{ km.}}

Part c

State the importance of considering speed when calculating total distance over the same time frame.

Speed is crucial because it directly determines the distance covered within a given time. Without considering speed, it's impossible to accurately calculate how far an object has traveled, as distance is the product of speed and time. Different speeds will result in different distances covered over the same time period.

Part 3

Concrete blocks of length 1425\frac{14}{25} m were laid end to end along the four sides of a rectangular lawn 28 m long and 21 m wide.

Part a

175 blocks175 \text{ blocks}

How many blocks were required to complete one layer?

  1. Calculate the perimeter of the rectangular lawn.

    Length of lawn, L=28 mL = 28 \text{ m}.
    Width of lawn, W=21 mW = 21 \text{ m}.
    Perimeter, P=2(L+W)P = 2(L + W)

    P=2(28 m+21 m)P = 2(28 \text{ m} + 21 \text{ m}) P=2(49 m)P = 2(49 \text{ m}) P=98 mP = 98 \text{ m}
  2. Identify the length of one concrete block.

    Length of one block =1425 m= \frac{14}{25} \text{ m}.

  3. Calculate the number of blocks required by dividing the perimeter by the length of one block.

    Number of blocks =PerimeterLength of one block= \frac{\text{Perimeter}}{\text{Length of one block}}

    Number of blocks=981425\text{Number of blocks} = \frac{98}{\frac{14}{25}} Number of blocks=98×2514\text{Number of blocks} = 98 \times \frac{25}{14} Number of blocks=9814×25\text{Number of blocks} = \frac{98}{14} \times 25 Number of blocks=7×25\text{Number of blocks} = 7 \times 25 Number of blocks=175\text{Number of blocks} = 175

    175 blocks were required to complete one layer.

    175 blocks\boxed{175 \text{ blocks}}
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