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Consider the following set of marks for a class test (out of 10) for grade 8 A. Rearrange these marks in an ascending order, write down the mode, determine the median, calculate the mean, and calculate the range for this set.

Mathematics

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1:

The given set of marks is: $8, 6, 4, 10, 5, 8, 8, 6$.

1.1.1 Rearrange these marks in an ascending order

  1. List all the marks.

    The marks are $8, 6, 4, 10, 5, 8, 8, 6$.

  2. Arrange the marks from smallest to largest.

    4,5,6,6,8,8,8,104, 5, 6, 6, 8, 8, 8, 10

    The marks in ascending order are: 4, 5, 6, 6, 8, 8, 8, 10\boxed{\text{4, 5, 6, 6, 8, 8, 8, 10}}

    1.1.2 Write down the mode of this set of marks

  3. Identify the frequency of each mark in the sorted list.

    The sorted marks are $4, 5, 6, 6, 8, 8, 8, 10$.

    • 4 appears once.
    • 5 appears once.
    • 6 appears twice.
    • 8 appears three times.
    • 10 appears once.
  4. Determine the mark that appears most frequently.

    The mark that appears most often is 8.
    The mode is: 8\boxed{8}

    1.1.3 Determine the median for this set

  5. Use the sorted list of marks.

    The sorted marks are 4,5,6,6,8,8,8,104, 5, 6, 6, 8, 8, 8, 10.
    There are n=8n=8 marks, which is an even number.

  6. Find the two middle values.

    For an even number of data points, the median is the average of the (n2)\left(\frac{n}{2}\right)-th and (n2+1)\left(\frac{n}{2} + 1\right)-th values.
    The (82)\left(\frac{8}{2}\right)-th value is the 4th value, which is 6.
    The (82+1)\left(\frac{8}{2} + 1\right)-th value is the 5th value, which is 8.

  7. Calculate the average of the two middle values.

    Median=6+82=142=7\text{Median} = \frac{6 + 8}{2} = \frac{14}{2} = 7

    The median is: 7\boxed{7}

    1.1.4 Calculate the mean for this set

  8. Sum all the marks.

    Sum=4+5+6+6+8+8+8+10=55\text{Sum} = 4 + 5 + 6 + 6 + 8 + 8 + 8 + 10 = 55
  9. Count the total number of marks.

    There are 8 marks.

  10. Calculate the mean by dividing the sum by the number of marks.

    Mean=Sum of marksNumber of marks=558=6.875\text{Mean} = \frac{\text{Sum of marks}}{\text{Number of marks}} = \frac{55}{8} = 6.875

    The mean is: 6.875\boxed{6.875}

    1.1.5 Calculate the range for this set

  11. Identify the highest and lowest marks from the sorted list.

    The sorted marks are $4, 5, 6, 6, 8, 8, 8, 10$.
    Highest mark = 10
    Lowest mark = 4

  12. Calculate the difference between the highest and lowest marks.

    Range=Highest mark−Lowest mark=10−4=6\text{Range} = \text{Highest mark} - \text{Lowest mark} = 10 - 4 = 6

    The range is: 6\boxed{6}

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