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Construct a circle that touches points ABC. What is the radius of the circle? (3mks)

Mathematics

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Answer

46629.52 cm3\text{46629.52 cm}^3

Step-by-step solution

3 steps

Ili kukokotoa ujazo wa frustum, tutatoa ujazo wa koni ndogo iliyokatwa kutoka kwenye ujazo wa koni kubwa ya asili.

Kutokana na maelezo:

  • Urefu wa frustum (HfH_f) = 40 cm40 \text{ cm}
  • Radiasi kubwa (RR) = 30 cm30 \text{ cm}
  • Radiasi ndogo (rr) = 7 cm7 \text{ cm}
  • Urefu wa koni ndogo iliyokatwa (hh) = 10 cm10 \text{ cm}

Hii inamaanisha:

  • Koni kubwa ina radiasi R=30 cmR = 30 \text{ cm} na urefu jumla H=Hf+h=40 cm+10 cm=50 cmH = H_f + h = 40 \text{ cm} + 10 \text{ cm} = 50 \text{ cm}.
  • Koni ndogo ina radiasi r=7 cmr = 7 \text{ cm} na urefu h=10 cmh = 10 \text{ cm}.

Fomula ya ujazo wa koni ni V=13πr2hV = \frac{1}{3} \pi r^2 h. Tutatumia π=227\pi = \frac{22}{7}.

  1. Kokotoa ujazo wa koni kubwa.

    Ujazo wa koni kubwa (VLV_L) hutumia radiasi R=30 cmR = 30 \text{ cm} na urefu H=50 cmH = 50 \text{ cm}.

    VL=13πR2HV_L = \frac{1}{3} \pi R^2 H VL=13×227×(30 cm)2×(50 cm)V_L = \frac{1}{3} \times \frac{22}{7} \times (30 \text{ cm})^2 \times (50 \text{ cm}) VL=13×227×900 cm2×50 cmV_L = \frac{1}{3} \times \frac{22}{7} \times 900 \text{ cm}^2 \times 50 \text{ cm} VL=227×300 cm2×50 cmV_L = \frac{22}{7} \times 300 \text{ cm}^2 \times 50 \text{ cm} VL=227×15000 cm3V_L = \frac{22}{7} \times 15000 \text{ cm}^3 VL=3300007 cm3V_L = \frac{330000}{7} \text{ cm}^3 VL≈47142.8571 cm3V_L \approx 47142.8571 \text{ cm}^3
  2. Kokotoa ujazo wa koni ndogo iliyokatwa.

    Ujazo wa koni ndogo (VSV_S) hutumia radiasi r=7 cmr = 7 \text{ cm} na urefu h=10 cmh = 10 \text{ cm}.

    VS=13πr2hV_S = \frac{1}{3} \pi r^2 h VS=13×227×(7 cm)2×(10 cm)V_S = \frac{1}{3} \times \frac{22}{7} \times (7 \text{ cm})^2 \times (10 \text{ cm}) VS=13×227×49 cm2×10 cmV_S = \frac{1}{3} \times \frac{22}{7} \times 49 \text{ cm}^2 \times 10 \text{ cm} VS=13×22×7 cm2×10 cmV_S = \frac{1}{3} \times 22 \times 7 \text{ cm}^2 \times 10 \text{ cm} VS=15403 cm3V_S = \frac{1540}{3} \text{ cm}^3 VS≈513.3333 cm3V_S \approx 513.3333 \text{ cm}^3
  3. Kokotoa ujazo wa frustum.

    Ujazo wa frustum (VfV_f) ni tofauti kati ya ujazo wa koni kubwa na ujazo wa koni ndogo.

    Vf=VL−VSV_f = V_L - V_S Vf=3300007 cm3−15403 cm3V_f = \frac{330000}{7} \text{ cm}^3 - \frac{1540}{3} \text{ cm}^3

    Ili kutoa, tunahitaji kupata kigawo cha kawaida, ambacho ni 21.

    Vf=330000×321 cm3−1540×721 cm3V_f = \frac{330000 \times 3}{21} \text{ cm}^3 - \frac{1540 \times 7}{21} \text{ cm}^3 Vf=99000021 cm3−1078021 cm3V_f = \frac{990000}{21} \text{ cm}^3 - \frac{10780}{21} \text{ cm}^3 Vf=990000−1078021 cm3V_f = \frac{990000 - 10780}{21} \text{ cm}^3 Vf=97922021 cm3V_f = \frac{979220}{21} \text{ cm}^3 Vf≈46629.5238 cm3V_f \approx 46629.5238 \text{ cm}^3

    Ukizungusha hadi sehemu mbili za desimali:

    Vf≈46629.52 cm3V_f \approx 46629.52 \text{ cm}^3

    Ujazo wa frustum ni:

    46629.52 cm3\text{46629.52 cm}^3
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