We read your photo as:

In the given figure, a circle touches all the four sides of quadrilateral ABCD with AB = 6 cm, BC = 7 cm and CD = 4 cm. The length AD is

Mathematics

ScanSolve AI Answer

Step-by-step solution

6 steps

Q5

  1. A circle touches all four sides of quadrilateral ABCDABCD, so it is tangential.

    Sums of lengths of opposite sides are equal.

    AB+CD=AD+BCAB + CD = AD + BC
  2. Substitute given lengths (all in cm).

    6+4=AD+76 + 4 = AD + 7
  3. Simplify and solve for ADAD.

    10=AD+710 = AD + 7

    AD=10−7=3AD = 10 - 7 = 3 cm

    Answer: 3 cm (option 2)

    3

    Q6

  4. In an A.P., the difference between terms is (m−k)d(m - k)d, where dd is common difference.

    Assume standard: an−apa_n - a_p where n−p=2n - p = 2 (common in such problems, e.g., a4−a2a_4 - a_2 or a3−a1a_3 - a_1).

  5. Substitute d=3d = 3 cm?

    No units for AP, but numerical.

    an−ap=(n−p)d=2×3=6a_n - a_p = (n - p)d = 2 \times 3 = 6

    Answer: 6 (option 2)

    6

    Q7

  6. For A.P., first term a=1a = 1, last term l=11l = 11, sum $S_n

Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question