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Construct a grouped frequency distribution table and calculate the mean mark and standard deviation given a set of data and an assumed mean.
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4 stepshere's the solution for question 12:
a) Construct a grouped frequency distribution table using the class interval 20-29, 30-39, 40-49...
Define class intervals and tally the given marks.
The marks are:
29 52 37 79 63 48 65 46 54 32 51 66 74 24 35 61 58 39 49 53
45 58 56 38 59 28 50 49 67 56 37 45 79 68 43 66 26 47 55 71The class intervals are:
20-29
30-39
40-49
50-59
60-69
70-79Count the frequency for each class interval.
- 20-29: 29, 24, 28, 26 (4 marks)
- 30-39: 37, 32, 35, 39, 38, 37 (6 marks)
- 40-49: 48, 46, 49, 45, 49, 43, 45, 47 (8 marks)
- 50-59: 52, 54, 51, 53, 58, 58, 56, 59, 50, 56, 55 (11 marks)
- 60-69: 63, 65, 66, 61, 67, 68, 66 (7 marks)
- 70-79: 79, 74, 79, 71 (4 marks)
Construct the frequency distribution table.
b) Using an assumed mean of 54.5, calculate, correct to the nearest whole number, the:
(i) mean mark;
(ii) standard deviation of the distribution.
Create an extended frequency table to calculate class marks (), deviations (), , and .
The assumed mean .
The class mark is the midpoint of each interval. For example, for 20-29, .
The deviation .(i) Calculate the mean mark.
The formula for the mean using an assumed mean is .Correct to the nearest whole number, the mean mark is .
(ii) Calculate the standard deviation of the distribution.
The formula for standard deviation using an assumed mean is .Correct to the nearest whole number, the standard deviation is .
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