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Construct a multiplication table for modulo 9 on the set 2, 4, 6, 8. Then find the truth set of n n = n − 6 and evaluate (6 4) (4 2).

Mathematics

ScanSolve AI Answer

Answer

ii

29\mathbf{29}

5.9\mathbf{5.9}

23\mathbf{23}

Step-by-step solution

8 steps

Here are the solutions to the problems.

2. (a) Construct a multiplication ⊗\otimes table for modulo 9 on the set {2,4,6,8}\{2, 4, 6, 8\}.

Step 1: Create a table and calculate each product a×b(mod9)a \times b \pmod{9} for a,b∈{2,4,6,8}a, b \in \{2, 4, 6, 8\}.
For example, 2⊗2=(2×2)(mod9)=4(mod9)=42 \otimes 2 = (2 \times 2) \pmod{9} = 4 \pmod{9} = 4.
2⊗6=(2×6)(mod9)=12(mod9)=32 \otimes 6 = (2 \times 6) \pmod{9} = 12 \pmod{9} = 3.
6⊗8=(6×8)(mod9)=48(mod9)=36 \otimes 8 = (6 \times 8) \pmod{9} = 48 \pmod{9} = 3.
8⊗8=(8×8)(mod9)=64(mod9)=18 \otimes 8 = (8 \times 8) \pmod{9} = 64 \pmod{9} = 1.

The completed multiplication table is:

⊗246824837487656360387531\begin{array}{|c|c|c|c|c|} \hline \otimes & 2 & 4 & 6 & 8 \\ \hline 2 & 4 & 8 & 3 & 7 \\ \hline 4 & 8 & 7 & 6 & 5 \\ \hline 6 & 3 & 6 & 0 & 3 \\ \hline 8 & 7 & 5 & 3 & 1 \\ \hline \end{array}

2. (b) i. Using the table, find the truth set of n⊗n=n−6n \otimes n = n - 6.

Step 1: Test each value of nn from the set {2,4,6,8}\{2, 4, 6, 8\} in the equation n⊗n=n−6n \otimes n = n - 6.
For n=2n=2: 2⊗2=42 \otimes 2 = 4. 2−6=−42 - 6 = -4. 4≠−44 \neq -4.
For n=4n=4: 4⊗4=74 \otimes 4 = 7. 4−6=−24 - 6 = -2. 7≠−27 \neq -2.
For n=6n=6: 6⊗6=06 \otimes 6 = 0. 6−6=06 - 6 = 0. 0=00 = 0. This is true.
For n=8n=8: 8⊗8=18 \otimes 8 = 1. 8−6=28 - 6 = 2. 1≠21 \neq 2.

Step 2: Identify the values of nn for which the equation holds true.
The only value for which the equation is true is n=6n=6.
The truth set is {6}\boxed{\mathbf{\{6\}}}.

2. (b) ii. Evaluate (6⊗4)⊗(4⊗2)(6 \otimes 4) \otimes (4 \otimes 2).

Step 1: Evaluate the expression inside the first parenthesis, 6⊗46 \otimes 4, using the table.

6⊗4=66 \otimes 4 = 6

Step 2: Evaluate the expression inside the second parenthesis, 4⊗24 \otimes 2, using the table.

4⊗2=84 \otimes 2 = 8

Step 3: Substitute these results back into the original expression and evaluate.

(6⊗4)⊗(4⊗2)=6⊗8(6 \otimes 4) \otimes (4 \otimes 2) = 6 \otimes 8

From the table, 6⊗8=36 \otimes 8 = 3.
The evaluation is 3\boxed{\mathbf{3}}.

3. (a) The scores obtained by 10 students in a test have the following statistics: ∑x=290\sum x = 290 and ∑x2=8469\sum x^2 = 8469. Calculate:

Part i

The mean

Part ii

29\mathbf{29}

The variance

Given: Number of students N=10N = 10, ∑x=290\sum x = 290, ∑x2=8469\sum x^2 = 8469.

3. (a) i. The mean

  1. Use the formula for the mean, xˉ=∑xN\bar{x} = \frac{\sum x}{N}.

    xˉ=29010\bar{x} = \frac{290}{10}
  2. Calculate the mean.

    xˉ=29\bar{x} = 29

    The mean is 29\boxed{\mathbf{29}}.

    3. (a) ii. The variance

  3. Use the formula for variance, σ2=∑x2N−(xˉ)2\sigma^2 = \frac{\sum x^2}{N} - (\bar{x})^2.

    σ2=846910−(29)2\sigma^2 = \frac{8469}{10} - (29)^2
  4. Perform the division and squaring.

    σ2=846.9−841\sigma^2 = 846.9 - 841
  5. Calculate the variance.

    σ2=5.9\sigma^2 = 5.9

    The variance is 5.9\boxed{\mathbf{5.9}}.

    3. (b) The mean of 14 numbers is 19. If each of the numbers is increased by 4. What is the new mean?

  6. Understand the effect of adding a constant to each number in a set.

    If each number in a set is increased by a constant value, the mean of the set also increases by that same constant value.

  7. Add the increase to the original mean.

    New Mean=Original Mean+Increase\text{New Mean} = \text{Original Mean} + \text{Increase} New Mean=19+4\text{New Mean} = 19 + 4
  8. Calculate the new mean.

    New Mean=23\text{New Mean} = 23

    The new mean is 23\boxed{\mathbf{23}}.

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