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Convert the complex number (1)/(1+i) to a+ib form.

Mathematics

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Step 1: Convert the complex number 11+i\frac{1}{1+i} to a+iba+ib form.
To do this, multiply the numerator and the denominator by the conjugate of the denominator. The conjugate of 1+i1+i is 1−i1-i.

11+i=11+i×1−i1−i\frac{1}{1+i} = \frac{1}{1+i} \times \frac{1-i}{1-i}

Step 2: Perform the multiplication.
The numerator becomes 1×(1−i)=1−i1 \times (1-i) = 1-i.
The denominator becomes (1+i)(1−i)(1+i)(1-i). Using the difference of squares formula (a+b)(a−b)=a2−b2(a+b)(a-b) = a^2 - b^2:

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