Copy and Complete the table y = x2 - 2x − 2 for −4

Question

Copy and Complete the table y = x2 - 2x − 2 for −4 <= x <= 4

ScanSolve AI Tutor · Accepted Answer

To complete the table, we substitute each value of $x$ into the equation $y = x^2 - 2x - 2$ .

Calculate $y$ for each $x$ value.
For $x = -4$ : $y = (-4)^2 - 2(-4) - 2 = 16 + 8 - 2 = 22$
For $x = -3$ : $y = (-3)^2 - 2(-3) - 2 = 9 + 6 - 2 = 13$
For $x = -2$ : $y = (-2)^2 - 2(-2) - 2 = 4 + 4 - 2 = 6$
For $x = -1$ : $y = (-1)^2 - 2(-1) - 2 = 1 + 2 - 2 = 1$
For $x = 0$ : $y = (0)^2 - 2(0) - 2 = 0 - 0 - 2 = -2$
For $x = 1$ : $y = (1)^2 - 2(1) - 2 = 1 - 2 - 2 = -3$
For $x = 2$ : $y = (2)^2 - 2(2) - 2 = 4 - 4 - 2 = -2$
For $x = 3$ : $y = (3)^2 - 2(3) - 2 = 9 - 6 - 2 = 1$
For $x = 4$ : $y = (4)^2 - 2(4) - 2 = 16 - 8 - 2 = 6$
Complete the table with the calculated $y$ values.
$\begin{array}{|c|c|c|c|c|c|c|c|c|c|} \hline x & -4 & -3 & -2 & -1 & 0 & 1 & 2 & 3 & 4 \\ \hline y & 22 & 13 & 6 & 1 & -2 & -3 & -2 & 1 & 6 \\ \hline \end{array}$
The completed table is:
$\boxed{ \begin{array}{|c|c|c|c|c|c|c|c|c|c|} \hline x & -4 & -3 & -2 & -1 & 0 & 1 & 2 & 3 & 4 \\ \hline y & \textbf{22} & \textbf{13} & \textbf{6} & \textbf{1} & \textbf{-2} & \textbf{-3} & \textbf{-2} & \textbf{1} & \textbf{6} \\ \hline \end{array} }$

Copy and Complete the table y = x2 − 2x − 2 for -4 <= x <= 4