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Find the derivation of each of the following expressions. a. 3x 2+2x+3 / 2x2 b. (3x+2)(x-2) c. Evaluate Limit by factoring Lim x->4 (x2-x-12)/(x2+x-20)

Mathematics

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Here's the derivation for question 1.a:

  1. Rewrite the expression by dividing each term in the numerator by the denominator.

    Y=3x2+2x+32x2Y = \frac{3x^2 + 2x + 3}{2x^2} Y=3x22x2+2x2x2+32x2Y = \frac{3x^2}{2x^2} + \frac{2x}{2x^2} + \frac{3}{2x^2} Y=32+1x+32x−2Y = \frac{3}{2} + \frac{1}{x} + \frac{3}{2}x^{-2} Y=32+x−1+32x−2Y = \frac{3}{2} + x^{-1} + \frac{3}{2}x^{-2}
  2. Differentiate each term with respect to xx.

    Recall that ddx(c)=0\frac{d}{dx}(c) = 0 for a constant cc, and ddx(xn)=nxn−1\frac{d}{dx}(x^n) = nx^{n-1}.

    dYdx=ddx(32)+ddx(x−1)+ddx(32x−2)\frac{dY}{dx} = \frac{d}{dx}\left(\frac{3}{2}\right) + \frac{d}{dx}(x^{-1}) + \frac{d}{dx}\left(\frac{3}{2}x^{-2}\right) dYdx=0+(−1)x−1−1+32(−2)x−2−1\frac{dY}{dx} = 0 + (-1)x^{-1-1} + \frac{3}{2}(-2)x^{-2-1} dYdx=−x−2−3x−3\frac{dY}{dx} = -x^{-2} - 3x^{-3}
  3. Rewrite the expression with positive exponents.

    dYdx=−1x2−3x3\frac{dY}{dx} = -\frac{1}{x^2} - \frac{3}{x^3}

    The derivation is:

    −1x2−3x3\boxed{-\frac{1}{x^2} - \frac{3}{x^3}}
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