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To find the coordinates of the point on the curve where the gradient is 4:
Step 1: Find the derivative of the curve y=x2−2x+6.
The gradient function, dxdy, is found by differentiating the equation with respect to x.
dxdy=dxd(x2−2x+6)
dxdy=2x−2
Step 2: Set the gradient equal to 4 and solve for x.
2x−2=4
2x=4+2
2x=6
x=26
x=3
Step 3: Substitute the value of x back into the original curve equation to find the corresponding y coordinate.
y=x2−2x+6
y=(3)2−2(3)+6
y=9−6+6
y=9
Step 4: State the coordinates of the point.
The coordinates of the point are (x,y)=(3,9).
The coordinates are (3,9).
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To find the number of Sh 50 notes and Sh 20 coins:
Step 1: Define variables.
Let n be the number of Sh 50 notes.
Let c be the number of Sh 20 coins.
Step 2: Formulate equations based on the given conditions.
Condition 1: She has 3 times as many Sh 20 coins as Sh 50 notes.
c=3n(1)
Condition 2: Altogether she has Sh 3400.
The total value is the sum of the value of notes and coins.
50n+20c=3400(2)
Step 3: Solve the system of equations.
Substitute equation (1) into equation (2):
50n+20(3n)=3400
50n+60n=3400
110n=3400
n=1103400
n=11340
n=30.909...
There seems to be an issue with the numbers provided in the question, as the number of notes/coins must be an integer. Let's re-check the calculation.
If n must be an integer, then 3400 must be divisible by 110. 3400/110=340/11, which is not an integer.
Assuming there might be a typo in the total amount or the ratio, and proceeding with the given numbers to show the method. If the total amount was, for example, Sh 3300, then n=3300/110=30.
Let's assume the total amount was intended to be Sh 3300 for integer results.
If 110n=3300, then n=30.
Then c=3n=3(30)=90.
Number of Sh 50 notes = 30, Number of Sh 20 coins = 90.
Total value = 50(30)+20(90)=1500+1800=3300.
Given the exact numbers in the problem, an integer solution for the number of notes/coins is not possible. This indicates a potential error in the problem statement itself.
However, if we must provide an answer based on the given numbers:
n=1103400≈30.91
c=3n=3×1103400=11010200≈92.73
Since the number of notes and coins must be whole numbers, this problem as stated does not yield an integer solution. If we assume the total amount was Sh 3300:
Number of Sh 50 notes: 30
Number of Sh 20 coins: 90
(Note: This assumes a slight adjustment to the total amount to allow for integer counts of notes/coins.)
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To find how many days the remaining workers would take to complete the work:
Step 1: Calculate the total amount of work in "worker-days".
Initial workers = 45
Initial days to complete = 10
TotalWork=45workers×10days=450worker−days
Step 2: Calculate the amount of work done in the first 4 days.
Workers for the first 4 days = 45
Days worked = 4
WorkDone=45workers×4days=180worker−days
Step 3: Calculate the remaining work.
RemainingWork=TotalWork−WorkDone
RemainingWork=450worker−days−180worker−days=270worker−days
Step 4: Determine the number of remaining workers.
Initial workers = 45
Workers laid off = 15
RemainingWorkers=45−15=30workers
Step 5: Calculate the number of days the remaining workers will take to complete the remaining work.
DaysNeeded=RemainingWorkersRemainingWork
DaysNeeded=30workers270worker−days=9days
The remaining workers would take 9days to complete the work.