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Find the derivative of the function y = (x2 + 7x) / (x+2) using the quotient rule.

Mathematics

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Answer

dydx=x2+4x+14(x+2)2\frac{dy}{dx} = \frac{x^2 + 4x + 14}{(x+2)^2}

Graph of y = (x² + 7x)/(x + 2)

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Key points of y = (x² + 7x)/(x + 2)
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x-intercept−70
x-intercept00

Step-by-step solution

5 steps

To find dydx\frac{dy}{dx} for the given function y=x2+7xx+2y = \frac{x^2 + 7x}{x+2}, we will use the quotient rule.

The quotient rule states that if y=uvy = \frac{u}{v}, then dydx=vdudx−udvdxv2\frac{dy}{dx} = \frac{v \frac{du}{dx} - u \frac{dv}{dx}}{v^2}.

  1. Identify uu and vv.

    Let u=x2+7xu = x^2 + 7x
    Let v=x+2v = x+2

  2. Find the derivatives of uu and vv with respect to xx.

    dudx=ddx(x2+7x)=2x+7\frac{du}{dx} = \frac{d}{dx}(x^2 + 7x) = 2x + 7 dvdx=ddx(x+2)=1\frac{dv}{dx} = \frac{d}{dx}(x+2) = 1
  3. Apply the quotient rule formula.

    dydx=(x+2)(2x+7)−(x2+7x)(1)(x+2)2\frac{dy}{dx} = \frac{(x+2)(2x+7) - (x^2+7x)(1)}{(x+2)^2}
  4. Expand and simplify the numerator.

    Numerator=(x⋅2x+x⋅7+2⋅2x+2⋅7)−(x2+7x)\text{Numerator} = (x \cdot 2x + x \cdot 7 + 2 \cdot 2x + 2 \cdot 7) - (x^2 + 7x) Numerator=(2x2+7x+4x+14)−(x2+7x)\text{Numerator} = (2x^2 + 7x + 4x + 14) - (x^2 + 7x) Numerator=2x2+11x+14−x2−7x\text{Numerator} = 2x^2 + 11x + 14 - x^2 - 7x Numerator=(2x2−x2)+(11x−7x)+14\text{Numerator} = (2x^2 - x^2) + (11x - 7x) + 14 Numerator=x2+4x+14\text{Numerator} = x^2 + 4x + 14
  5. Write the final expression for dydx\frac{dy}{dx}.

    dydx=x2+4x+14(x+2)2\frac{dy}{dx} = \boxed{\frac{x^2 + 4x + 14}{(x+2)^2}}
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