Explain how did we get f(x+h)2

Mathematics

ScanSolve AI Answer

Answer

x2+2xh+h2x^2 + 2xh + h^2

Step-by-step solution

3 steps

It seems there might be a slight misunderstanding in the notation. For the function f(x)=x2f(x) = x^2, we are looking for f(x+h)f(x+h), not f(x+h)2f(x+h)^2.

Here's how we get f(x+h)f(x+h):

  1. Understand the function definition.

    The function is defined as f(input)=(input)2f(\text{input}) = (\text{input})^2. Whatever is inside the parentheses of f(⋅)f(\cdot) gets squared.

  2. Substitute (x+h)(x+h) as the input.

    When we want to find f(x+h)f(x+h), we replace every instance of xx in the original function f(x)=x2f(x) = x^2 with (x+h)(x+h).
    So, f(x+h)=(x+h)2f(x+h) = (x+h)^2.

  3. Expand the expression (x+h)2(x+h)^2.

    This is a standard algebraic expansion:

    (x+h)2=(x+h)(x+h)(x+h)^2 = (x+h)(x+h) (x+h)2=x⋅x+x⋅h+h⋅x+h⋅h(x+h)^2 = x \cdot x + x \cdot h + h \cdot x + h \cdot h (x+h)2=x2+xh+xh+h2(x+h)^2 = x^2 + xh + xh + h^2 (x+h)2=x2+2xh+h2(x+h)^2 = x^2 + 2xh + h^2

    So, f(x+h)f(x+h) is equal to x2+2xh+h2\boxed{x^2 + 2xh + h^2}.

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