How did you get the quotient

The numbers in the bottom row were $3, 7, -6, 0$.
The last number, 0, is the remainder. The numbers before it, $3, 7, -6$, are the coefficients of the quotient.

Since the original polynomial was $3x^3 + 4x^2 - 13x + 6$ (a cubic polynomial, degree 3) and we divided by a linear factor $(x-1)$ (degree 1), the quotient polynomial will have a degree of $3-1=2$.

The coefficients $3, 7, -6$ correspond to the terms of a quadratic polynomial ($ax^2 + bx + c$).
The first coefficient, 3, is for $x^2$.
The second coefficient, 7, is for $x$.
The third coefficient, $-6$, is the constant term.
Thus, the quotient is $3x^2 + 7x - 6$.