Calculate the distance from P to R to the nearest unit.

The diagram shows a line segment from Q to PR, labeled 8. This segment represents the altitude from Q to PR. Let's call the point where this altitude meets PR as M. So, $QM = 8$.
We are given the lengths of $PQ = 16$ and $QR = 10$.
We need to find the total length of PR, which is $PM + MR$.

$\triangle QMR$ is a right-angled triangle with the right angle at M.
The hypotenuse is QR, and the legs are QM and MR.

Substitute the known values:

Subtract 64 from both sides:

Take the square root of both sides:

$\triangle PQM$ is also a right-angled triangle with the right angle at M.
The hypotenuse is PQ, and the legs are QM and PM.

Substitute the known values:

Subtract 64 from both sides:

Take the square root of both sides:

To simplify $\sqrt{192}$, find the largest perfect square factor: $192 = 64 \times 3$.

The distance PR is the sum of PM and MR.

Using the approximate value $\sqrt{3} \approx 1.73205$:

Rounding to the nearest unit:

The distance from P to R is approximately 20 units.

The distance from P to R is $\text{20 units}$.