Do a table of modulo 6 for me in division ➗

Mathematics

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Let's create a division table modulo 6. In modular arithmetic, division a ÷ b (mod n) is defined as finding a number x such that b · x ≡ a (mod n). This is equivalent to multiplying 'a' by the multiplicative inverse of 'b', denoted b⁻¹, where b · b⁻¹ ≡ 1 (mod n). A multiplicative inverse b⁻¹ exists only if the greatest common divisor (gcd) of b and n is 1.

  1. Identify numbers with multiplicative inverses modulo 6.

    For modulo 6, we consider numbers in the set {0, 1, 2, 3, 4, 5}.

    • For b = 0: Division by zero is undefined.
    • For b = 1: gcd(1, 6) = 1. The inverse is 1⁻¹ = 1 (since 1 × 1 = 1 mod 6).
    • For b = 2: gcd(2, 6) = 2 ≠ 1. No multiplicative inverse exists.
    • For b = 3: gcd(3, 6) = 3 ≠ 1. No multiplicative inverse exists.
    • For b = 4: gcd(4, 6) = 2 ≠ 1. No multiplicative inverse exists.
    • For b = 5: gcd(5, 6) = 1. The inverse is 5⁻¹ = 5 (since 5 × 5 = 25 ≡ 1 mod 6).
  2. Calculate the division results.

    For each 'a' (dividend) and 'b' (divisor), we calculate a ÷ b (mod 6). If b⁻¹ exists, the result is (a × b⁻¹) mod 6. If b⁻¹ does not exist or b = 0, the division is undefined or has no unique solution. We will denote these cases as "N/A".

  3. Construct the division table modulo 6.

    The rows represent the dividend 'a', and the columns represent the divisor 'b'.

    Division Table Modulo 6

    a \ b012345
    0N/A0N/AN/AN/A0
    1N/A1N/AN/AN/A5
    2N/A2N/AN/AN/A4
    3N/A3N/AN/AN/A3
    4N/A4N/AN/AN/A2
    5N/A5N/AN/AN/A1

    Explanation of "N/A" entries:

    • The column for b = 0 is N/A because division by zero is undefined.
    • The columns for b = 2, 3, and 4 are N/A because these numbers do not have a unique multiplicative inverse modulo 6 (their gcd with 6 is not 1).
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