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Draw a neat graph of f(x) and f⁻¹(x) on the same system of axes, clearly showing endpoints and the line of reflection.

Mathematics

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Answer

y=xy=x

I've already provided the solutions for parts 2.3.1 through 2.3.5 in the previous message.

For question 2.3.6, which asks for a graph, I will describe how to draw it, as I cannot directly create an image.

2.3.6 Draw a neat graph of f(x)f(x) and f−1(x)f^{-1}(x) on the same system of axes on ADDENDUM A (attached), clearly showing the nature of the start and endpoints on the graphs. Also show the line about which f(x)f(x) reflects f−1(x)f^{-1}(x) and label it.

To draw the graph:

  • Graph of f(x)=2x+3f(x) = 2x+3:

    • The domain for f(x)f(x) is x∈[−1,2)x \in [-1, 2).
    • Calculate the starting point: When x=−1x = -1, f(−1)=2(−1)+3=1f(-1) = 2(-1) + 3 = 1. Plot a closed circle at the coordinate (−1,1)(-1, 1) because x≥−1x \ge -1.
    • Calculate the ending point: When x=2x = 2, f(2)=2(2)+3=7f(2) = 2(2) + 3 = 7. Plot an open circle at the coordinate (2,7)(2, 7) because x<2x < 2.
    • Draw a straight line connecting these two points.
  • Graph of f−1(x)=x−32f^{-1}(x) = \frac{x-3}{2}:

    • The domain for f−1(x)f^{-1}(x) is x∈[1,7)x \in [1, 7), which is the range of f(x)f(x).
    • Calculate the starting point: When x=1x = 1, f−1(1)=1−32=−1f^{-1}(1) = \frac{1-3}{2} = -1. Plot a closed circle at the coordinate (1,−1)(1, -1).
    • Calculate the ending point: When x=7x = 7, f−1(7)=7−32=2f^{-1}(7) = \frac{7-3}{2} = 2. Plot an open circle at the coordinate (7,2)(7, 2).
    • Draw a straight line connecting these two points.
  • Line of reflection:

    • Draw a dashed or solid line representing the equation y=xy=x. This line should pass through the origin (0,0)(0,0) and points like (1,1)(1,1), (2,2)(2,2), etc.
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